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3 years ago

5

Plzzzz help !!!! ill mark you brainliest

1 answer:

xz_007 [3.2K]3 years ago

8 0

Answer:

It is a

Step-by-step explanation:

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James states that quadrilateral

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$AD=\sqrt{(-1-3)^{2}+(-3-(-4))^{2}}=\sqrt{17}\\\\BC=\sqrt{(5-9)^{2}+(1-0)^{2}}=\sqrt{17} \\\\\therefore \overline{AD} \cong \overline{BC}$

$AB=\sqrt{(-1-5)^{2}+(-3-1)^{2}}=\sqrt{52}=2\sqrt{13}\\\\CD=\sqrt{(9-3)^{2}+(0-(-4))^{2}}=\sqrt{52}=2\sqrt{13}\\\\\therefore \overline{AB} \cong \overline{CD}$

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When adding or subtracting fractions, they must have the same denominator.

$\dfrac{5}{9}-\boxed{\dfrac{?}{?}}=\dfrac{12}{54}\\\\\\\dfrac{5}{9}\bigg(\dfrac{6}{6}\bigg)-\boxed{\dfrac{?}{?}}=\dfrac{12}{54}\\\\\\\dfrac{30}{54}-\boxed{\dfrac{?}{?}}=\dfrac{12}{54}\\\\\\\dfrac{30}{54}-\boxed{\dfrac{18}{54}}=\dfrac{12}{54}\\\\\\\text{Simplify}\quad \dfrac{18}{54}\div \dfrac{18}{18}\quad =\large\boxed{\dfrac{1}{3}}$

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Roberto has a sample of an unknown liquid. The label in the bottle of the sample indicates that the liquid has a mass of 117 gra

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Step-by-step explanation:

The liquid in the bottle has mass given in grams and the mass of that substance is 117 grams.

The volume of the substance is 15 cubic centimeters.

Now, using the formula of density we can estimate which substance could it be.

$d=\frac{m}{v}$ , where 'd', is the density, 'm' is the mass, and 'v' is the volume of the substance.

Plugging the value of mass and volume we get:

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