The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Scale factor is 1/3
And I think it's an enlargement
Answer:
The measure of angle E is:
m∠E = 80°
Step-by-step explanation:
Given
The triangle ΔDEF
It is stated that DE=EF and G is the midpoint of EF.
It means the midpoint G has converted the triangle into two equal right-angles triangles ΔDEG and ΔDFG with the right-angle at G.
Given
m∠GDE = 10°
As the right-angle triangle, ΔDEG lies at the right-angle G.
So, m∠DGE = 90°
as
m∠GDE = 10°
m∠DGE = 90°
m∠E = ?
We know that the sum of angles of a triangle is 180°.
m∠GDE + m∠DGE + m∠E = 180°
10° + 90° + m∠E = 180°
100 + m∠E = 180°
m∠E = 180° - 100
m∠E = 80°
Therefore,
The measure of angle E is: m∠E = 80°
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