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S_A_V [24]
3 years ago
5

Solve for t. 4=12gt^2

Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0

Answer:

t =  \sqrt{ \frac{8}{g} }

Step-by-step explanation:

We are solving for t.

4 =  \frac{1}{2} g {t}^{2}

Multiply both sides by 2.

8 = gt {}^{2}

Divide both sides by

\frac{8}{g}  =  {t}^{2}

Take square root of both sides.

t =  \sqrt{ \frac{8}{g} }

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Answer:

\large\boxed{(f-g)(x)=2x-3}

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)\\\\f(x)=3x-1,\ g(x)=x+2\\\\\text{substitute:}\\\\(f-g)(x)=(3x-1)-(x+2)\\\\=3x-1-x-2\qquad\text{combine like terms}\\\\=(3x-x)+(-1-2)\\\\=2x-3

7 0
3 years ago
In the distribution, the first quartile,median and mean are 30.8,48.5 and 42.0 respectively. If the co efficient skewness is -0.
finlep [7]

Answer:

The third quartile is 56.45

Step-by-step explanation:

The given parameters are;

The first quartile, Q₁ = 30.8

The median or second quartile, Q₂ = 48.5

The mean, \bar x = 42.0

Coefficient of skewness = -0.38

The Bowley's coefficient of skewness (SK) is given as follows;

SK = \dfrac{Q_3 + Q_1 - 2 \times Q_2}{Q_3 - Q_1}

Plugging in the values, we have;

-0.38 = \dfrac{Q_3 + 30.8 - 2 \times 48.5}{Q_3 - 30.8}

Which gives;

-0.38×(Q₃ - 30.8) = Q₃ + 30.8 - 2 × 48.5

11.704 - 0.38·Q₃ = Q₃ - 66.2

1.38·Q₃ = 11.704 + 66.2 =  77.904

Q₃ = 56.45

The third quartile = 56.45.

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-21 degrees

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-8+(-13)=-21

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