Answer:
![\displaystyle 2^{\frac{6}{5}}=2\sqrt[5]{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%202%5E%7B%5Cfrac%7B6%7D%7B5%7D%7D%3D2%5Csqrt%5B5%5D%7B2%7D)
Step-by-step explanation:
<u>Fractional Exponents</u>
An expression like
can be expressed as a radical of the form:
![\sqrt[m]{a^n}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Ba%5En%7D)
We have the expression:
Its equivalent radical form is:
![\displaystyle 2^{\frac{6}{5}}=\sqrt[5]{2^6}](https://tex.z-dn.net/?f=%5Cdisplaystyle%202%5E%7B%5Cfrac%7B6%7D%7B5%7D%7D%3D%5Csqrt%5B5%5D%7B2%5E6%7D)
Since the exponent is greater than the index of the radical, we can take 2 out of it by following the procedure:
![\sqrt[5]{2^6}=\sqrt[5]{2^5\cdot 2}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E6%7D%3D%5Csqrt%5B5%5D%7B2%5E5%5Ccdot%202%7D)
Taking out 
from the radical:
![\sqrt[5]{2^6}=2\sqrt[5]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E6%7D%3D2%5Csqrt%5B5%5D%7B2%7D)
Thus:
Answer:
Step-by-step explanation:
I just took the test it's
1 and 6
i hope it helps! :)
The answer is
the first one is x= 18.98
a^2+b^2=c^2
8 cm^2+17 cm^2= x^2
64+289=x^2
√x^2= √353
x=18.89
<span><span>the second one is x= 18.7
a^2+b^2=c^2
7 m^2+ x^2= 20 m^2
49 m+x^2=400 m
-49 -49
</span></span>√x^2=√352
<span><span>x= 18.7
Hope this helps!</span></span>
