A function has a horizontal asymptote at the value of y = a if the line y = a can be used to estimate the end behavior of a function and if f ( x ) → a as x → ∞ or x → − ∞ is the correct statement about horizontal asymptotes. Option A
<h3>What are horizontal asymptotes?</h3>
A horizontal asymptote of a graph can be defined as a horizontal line at y = b where the graph tend to approach the line as an inputs approach to infinity ( ∞ or –∞).
A slant asymptote of a graph is known as a slanted line y = mx + b where the graph approaches the line as the inputs approach the positive infinity ∞ or to the infinity –∞.
Thus, a function has a horizontal asymptote at the value of y = a if the line y = a can be used to estimate the end behavior of a function and if f ( x ) → a as x → ∞ or x → − ∞ is the correct statement about horizontal asymptotes. Option A
Learn more about horizontal asymptotes here:
brainly.com/question/1851758
#SPJ1
Answer:
2t-7
Step-by-step explanation:
distribute the 2, to the t and the -4
you should have 2t-8+1
then you add the 1 to the -8 and you get -7
resulting in 2t-7 being the answer
Answer:
a. The mean of the sample is M=35.
The variance of the sample is s^2=39.125.
The standard deviation of the sample is s=6.255.
b. z=-1.6
c. SEM = 2.212
Step-by-step explanation:
The mean of the sample is M=35.
The variance of the sample is s^2=39.125.
The standard deviation of the sample is s=6.255.
<u>Sample mean</u>
<u />
<u>Sample variance and standard deviation</u>
<u />![s^2=\dfrac{1}{(n-1)}\sum_{i=1}^{8}(x_i-M)^2\\\\\\s^2=\dfrac{1}{7}\cdot [(27-(35))^2+(25-(35))^2+(32-(35))^2+(40-(35))^2+(43-(35))^2+(37-(35))^2+(35-(35))^2+(38-(35))^2]\\\\\\](https://tex.z-dn.net/?f=s%5E2%3D%5Cdfrac%7B1%7D%7B%28n-1%29%7D%5Csum_%7Bi%3D1%7D%5E%7B8%7D%28x_i-M%29%5E2%5C%5C%5C%5C%5C%5Cs%5E2%3D%5Cdfrac%7B1%7D%7B7%7D%5Ccdot%20%5B%2827-%2835%29%29%5E2%2B%2825-%2835%29%29%5E2%2B%2832-%2835%29%29%5E2%2B%2840-%2835%29%29%5E2%2B%2843-%2835%29%29%5E2%2B%2837-%2835%29%29%5E2%2B%2835-%2835%29%29%5E2%2B%2838-%2835%29%29%5E2%5D%5C%5C%5C%5C%5C%5C)
![s^2=\dfrac{1}{7}\cdot [(58.141)+(92.641)+(6.891)+(28.891)+(70.141)+(5.64)+(0.14)+(11.39)]\\\\\ s^2=\dfrac{273.875}{7}=39.125\\\\\\s=\sqrt{39.125}=6.255](https://tex.z-dn.net/?f=s%5E2%3D%5Cdfrac%7B1%7D%7B7%7D%5Ccdot%20%5B%2858.141%29%2B%2892.641%29%2B%286.891%29%2B%2828.891%29%2B%2870.141%29%2B%285.64%29%2B%280.14%29%2B%2811.39%29%5D%5C%5C%5C%5C%5C%09%09%09%09%09%09%09%09%09%09%09%09s%5E2%3D%5Cdfrac%7B273.875%7D%7B7%7D%3D39.125%5C%5C%5C%5C%5C%5Cs%3D%5Csqrt%7B39.125%7D%3D6.255)
b. If the population mean is 45, the z-score for M=35 would be:
c. The standard error of the mean (SEM) of this group is calculated as:
Answer:
Tu divises 3.50$ par 24 cookies donc environ 14 centimes
