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2 years ago

Which of the following is the solution set of the given equation?

Mathematics

2 answers:

N76 [4]2 years ago

4 0

Answer:

x = -10

Step-by-step explanation:

GarryVolchara [31]2 years ago

3 0

Answer is -10
(x-3)-2(x+6)= -5
x-3-2x-12= -5
-x= -5+12+3
-x=10
x= -10

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A department store sells a pair of shoes with an 87% markup. If the store bought the pair of shoes for $55.25, what is the selli

kolbaska11 [484]

Markup means they sell it for that percentage more than they bought it for. First let's calculate how much they will mark it up for:

$\sf 55.25\cdot 87\%$

Convert 87% into a decimal(87/100):

$\sf 55.25\cdot 0.87$

Multiply:

$\sf\approx 48$

This is how much they'll mark it up, now let's add it to how much they bought it for to find out the selling price:

$\sf 48+55.25\approx\boxed{\sf \$ 103}$

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3 years ago

Someone please help me

allsm [11]

Answer:

Solutions: $x = \frac{-3}{ 4} + i \sqrt{39}$ , $x = \frac{-3}{4} - i \sqrt{39}$

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

$x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}$

$x = \frac{-3 +/- \sqrt{9- 48} }{4}$

$x = \frac{-3 +/- \sqrt{-39} }{4}$

$x = \frac{-3 + i \sqrt{39} }{4}$ , $x = \frac{-3 - i \sqrt{39} }{4}$

Therefore, the solutions to the given quadratic equation are:

$x = -\frac{3}{ 4} + i \sqrt{39}$ , $x = -\frac{3}{4} - i \sqrt{39}$

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2 years ago

What is the area of a circle with a radius of 21 cm?

Rzqust [24]

The area is 1,385,442

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artcher [175]

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Step-by-step explanation:

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3 years ago

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zvonat [6]

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