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Gemiola [76]
2 years ago
10

Your class is selling wrapping paper and candles. Rolls of paper sell for $7 and candles sell for $10 each. A total of 109 items

were sold and $931 was raised. How many of each item was sold? BEFORE 4 TODAY PLZZZZ ASAP
Mathematics
2 answers:
Klio2033 [76]2 years ago
8 0

Answer:

53 Rolls of paper and 56 Candles

Step-by-step explanation:

56 x $10 = $560

$7 x 53 = $371

$560 + $371 = $931

And 56 candles sold plus 53 rolls of paper sold equals 109 items sold

Phantasy [73]2 years ago
6 0
Ignore me I’m testing somethings
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Which number is not in scientific notation?
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Answer:

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Step-by-step explanation:

A 9 ⋅ 1019

B 7.8 ⋅ 106

C 1.45 ⋅ 10−7

D 0.33 ⋅ 10−15

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3 years ago
Identify a pair of supplementary angles in the figure. answers : 2 and 4 1 and 6 1 and 5 5 and 6
Nuetrik [128]

Answer:

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Step-by-step explanation:

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3 years ago
(3x-4y)^2-(3x-4y)(3x+4y)
zheka24 [161]

Answer:

-24xy + 32y^2

Step-by-step explanation:

Hello!

We can use the special binomial product formulas:

  • (a + b)^2 = a^2 + 2ab + b^2
  • (a + b)(a - b) = a^2 - b^2

<h3>Simplify</h3>
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6 0
2 years ago
A local company makes a candy that is supposed to weigh 1.00 ounces. A random sample of 25 pieces of candy produces a mean of 0.
AysviL [449]

Answer:

n=(\frac{2.58(0.004)}{0.001})^2 =106.50 \approx 107

So the answer for this case would be n=107 rounded up to the nearest integer

Step-by-step explanation:

Information given

\bar X= 0.996 the sample mean

s=0.004 the sample deviation

n =25 the sample size

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =0.001 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

We can use as estimator of the real population deviation the sample deviation for this case \hat \sigma = s/ The critical value for 99% of confidence interval is given by z_{\alpha/2}=2.58, replacing into formula (b) we got:

n=(\frac{2.58(0.004)}{0.001})^2 =106.50 \approx 107

So the answer for this case would be n=107 rounded up to the nearest integer

6 0
3 years ago
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