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Gemiola [76]
2 years ago
10

Your class is selling wrapping paper and candles. Rolls of paper sell for $7 and candles sell for $10 each. A total of 109 items

were sold and $931 was raised. How many of each item was sold? BEFORE 4 TODAY PLZZZZ ASAP
Mathematics
2 answers:
Klio2033 [76]2 years ago
8 0

Answer:

53 Rolls of paper and 56 Candles

Step-by-step explanation:

56 x $10 = $560

$7 x 53 = $371

$560 + $371 = $931

And 56 candles sold plus 53 rolls of paper sold equals 109 items sold

Phantasy [73]2 years ago
6 0
Ignore me I’m testing somethings
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3 years ago
I need help on this.
tatiyna

9514 1404 393

Answer:

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  (b)  $1340

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Step-by-step explanation:

(a) The debit card is funded by Jenny's checking account, so it cannot be used to spend more than her checking account balance. The most Jenny can spend using her debit card is $1430.

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(b) Amounts purchased using her credit card add to the credit balance. The most Jenny can purchase is the difference between her current balance and her credit limit.

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5 0
2 years ago
A coin is tossed twice. What is the probability of getting a tail in the first toss and a tail in the second toss?
skelet666 [1.2K]

Answer:

<h2>1/4 Chances</h2><h2>25% Chances</h2><h2>0.25 Chances (out of 1)</h2>

Step-by-step explanation:

Two methods to answer the question.

Here are presented to show the advantage in using the product rule given above.

<h2>Method 1:Using the sample space</h2>

The sample space S of the experiment of tossing a coin twice is given by the tree diagram shown below

The first toss gives two possible outcomes: T or H ( in blue)

The second toss gives two possible outcomes: T or H (in red)

From the three diagrams, we can deduce the sample space S set as follows

          S={(H,H),(H,T),(T,H),(T,T)}

with n(S)=4 where n(S) is the number of elements in the set S

tree diagram in tossing a coin twice

The event E : " tossing a coin twice and getting two tails " as a set is given by

          E={(T,T)}

with n(E)=1 where n(E) is the number of elements in the set E

Use the classical probability formula to find P(E) as:

          P(E)=n(E)n(S)=14

<h2>Method 2: Use the product rule of two independent event</h2>

Event E " tossing a coin twice and getting a tail in each toss " may be considered as two events

Event A " toss a coin once and get a tail " and event B "toss the coin a second time and get a tail "

with the probabilities of each event A and B given by

          P(A)=12 and P(B)=12

Event E occurring may now be considered as events A and B occurring. Events A and B are independent and therefore the product rule may be used as follows

        P(E)=P(A and B)=P(A∩B)=P(A)⋅P(B)=12⋅12=14

NOTE If you toss a coin a large number of times, the sample space will have a large number of elements and therefore method 2 is much more practical to use than method 1 where you have a large number of outcomes.

We now present more examples and questions on how the product rule of independent events is used to solve probability questions.

8 0
2 years ago
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The diameter of an ancient chariot wheel is 2 meters. What is the approximate distance the chariot travels if the wheel rotates
ohaa [14]
First we need to find the circumference
C= 2 pi r or C= d*pi
d=2 m
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distance traveled=6.28 m*120=753.60 m
7 0
3 years ago
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serg [7]

Answer:

better do what I do, add never goes wrong

Step-by-step explanation:

i lied it always does

7 0
2 years ago
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