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Gemiola [76]
2 years ago
10

Your class is selling wrapping paper and candles. Rolls of paper sell for $7 and candles sell for $10 each. A total of 109 items

were sold and $931 was raised. How many of each item was sold? BEFORE 4 TODAY PLZZZZ ASAP
Mathematics
2 answers:
Klio2033 [76]2 years ago
8 0

Answer:

53 Rolls of paper and 56 Candles

Step-by-step explanation:

56 x $10 = $560

$7 x 53 = $371

$560 + $371 = $931

And 56 candles sold plus 53 rolls of paper sold equals 109 items sold

Phantasy [73]2 years ago
6 0
Ignore me I’m testing somethings
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Answer -6

Step-by-step explanation:   -12+-6 =-6

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A culture started with 5000 bacteria. after 4 hours, it grew to 6000. Predict how many bacteria will be present after 17 hours
kykrilka [37]

Answer:

A culture started with 5000 bacteria. after 4 hours, it grew to 6000.

=> Increasing rate = difference/time = (6000 - 5000)/4 = 250 bacteria/hour

=> The number of bacteria after 17 hours:

N = 5000 + 250 x 17 = 9250 bacteria

Hope this helps!

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3 years ago
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Please help me answer this question
sergejj [24]

Answer:

72km

Step-by-step explanation:

alex : tomos : annabelle = 2 : 3 : 4

if tomos drove 24km

tomos ratio is 3

so 3 --> 24

<em>1 --> 8 </em>

<u>total ratios --> 2 + 3 + 4 = 9</u>

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2 years ago
2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0
3 years ago
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Please help me.
Paul [167]

Answer:

(1,K) hope i could help

Step-by-step explanation:

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3 years ago
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