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Murrr4er [49]
2 years ago
5

What is 23 1/3 as an improper fraction

Mathematics
1 answer:
katen-ka-za [31]2 years ago
4 0

Answer:

70/3

Step-by-step explanation:

  1. Multiply: 23*3
  2. 23*3=69
  3. Add: 69+1
  4. 69+1=70
  5. 70/3

<em>Hope this helped!! :)</em>

<em>Brainliest?!?!</em>

<em>Stay safe and have a wonderful day/afternoon/night!!!</em>

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Write an equation of the line that passes through (2 -5) and is parallel to the line 2y=3x+10
andrey2020 [161]

Step-by-step explanation:

Given equation is

2y = 3x + 10

3x - 2y + 10 = 0 .....i)

Any line parallel to line I) is

3x - 2y + k = 0 ......ii)

As the line two passes through the point ( 2 , - 5 ) Now substituting the values

3 * 2 - 2 * ( - 5) + k = 0

6 + 10 + k = 0

16 + k = 0

k = - 16

Now putting the value of k in equation two

3x - 2y + 16 = 0 is the required equation.

Hope it will help :)❤

8 0
3 years ago
What is the slope for the following equation 9x + 2y = 9
MArishka [77]

Slope of the equation is -9/2

Step-by-step explanation:

  • Step 1: Write the equation in slope-intercept form y = mx + b

9x + 2y = 9

2y = -9x + 9

y = -9/2 x + 9/2

⇒ Slope, m = -9/2

7 0
3 years ago
Shun is going to flip a fair coin 450 times.
Allisa [31]

Answer:

Close to around 225 times

Step-by-step explanation:

If the coin Shun is flipping is 2 sided the most linear anwser would be to make the prediction of it flipping on the tails side for a perfect total of 225.

6 0
3 years ago
Read 2 more answers
What's a non-included angle?
Thepotemich [5.8K]

Answer:

It is the side where the rays of the angles overlap. The "non-included" side in AAS can be either of the two sides that are not directly between the two angles being used.

7 0
2 years ago
Write an augmented matrix of each system. Then, solve each system using matrix notation. Describe the solution set in vector not
Naddik [55]

Answer:

The answer is below

Step-by-step explanation:

Given the system of equations:

x + y + 2z = 9

2x + 4y - 3z = 1

3x + 6y - 5z = 0

This system of equation can be solved using matrix. This done by first representing the equations as matrix and then solving:

The matrix form is:

\left[\begin{array}{ccc}1&1&2\\2&4&-3\\3&6&-5\end{array}\right]  \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}1&1&2\\2&4&-3\\3&6&-5\end{array}\right]  ^{-1} \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\

\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2&-17&11\\-1&11&-7\\0&3&-2\end{array}\right]   \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}1\\2\\3\end{array}\right]

5 0
2 years ago
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