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3 years ago

What is 23 1/3 as an improper fraction

Mathematics

1 answer:

katen-ka-za [31]3 years ago

4 0

Answer:

70/3

Step-by-step explanation:

Multiply: 23*3
23*3=69
Add: 69+1
69+1=70
70/3

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Number of ways = 6!
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How do you work out the rate, time and principal from the compound interest formula?

wlad13 [49]

Answer:

Part 1) $P=A/(1+\frac{r}{n})^{nt}$ (see the explanation)

Part 2) $r=n[\frac{A}{P}^{1/(nt)}-1]$ (see the explanation)

Part 3) $t=log(\frac{A}{P})/[(n)log(1+\frac{r}{n})]$ (see the explanation)

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part 1) Find the Principal P

The values of A,r,n and t are given

Isolate the variable P

$A=P(1+\frac{r}{n})^{nt}$

Divide both side by $(1+\frac{r}{n})^{nt}$

$P=A/(1+\frac{r}{n})^{nt}$

Part 2) Find the rate r

The values of A,P,n and t are given

Isolate the variable r

$A=P(1+\frac{r}{n})^{nt}$

Divide both sides by P

$\frac{A}{P} =(1+\frac{r}{n})^{nt}$

Elevated both sides to 1/(nt)

$\frac{A}{P}^{1/(nt)} =(1+\frac{r}{n})$

subtract 1 both sides

$\frac{A}{P}^{1/(nt)}-1 =\frac{r}{n}$

Multiply by n both sides

$r=n[\frac{A}{P}^{1/(nt)}-1]$

Part 3) Find the time t

The values of A,P,r and n are given

Isolate the variable t

$A=P(1+\frac{r}{n})^{nt}$

Divide both sides by P

$\frac{A}{P} =(1+\frac{r}{n})^{nt}$

Apply log both sides

$log(\frac{A}{P})=log(1+\frac{r}{n})^{nt}$

Apply property of exponents

$log(\frac{A}{P})=(nt)log(1+\frac{r}{n})$

Divide both side by $(n)log(1+\frac{r}{n})$

$t=log(\frac{A}{P})/[(n)log(1+\frac{r}{n})]$

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3 years ago

My coffee mug weighs 200 g and hold 260cm3 .

yarga [219]

The coffee mug when filled will weigh 460 g

<h3>Calculating mass</h3>

From the question, we are to determine the weight of the mug if filled with water

From the given information,

The weight of the coffee mug is 200 g and holds 260cm³.

If filled with water, the volume of the water will be 260cm³.

Now, we will determine the mass of this volume of water

Using the formula,

Density = Mass/Volume

∴ Mass = Density × Volume

Volume = 260 cm³

Density of water = 1 g/cm³

∴ Mass of the water = 1 × 260

Mass of the water = 260 g

Mass of the coffee mug when filled with water = Mass of the coffee mug when empty + Mass of water

Mass of the coffee mug when filled with water = 200 g + 260 g

Mass of the coffee mug when filled with water = 460 g

Hence, the coffee mug when filled will weigh 460 g

Learn more on Calculating mass here: brainly.com/question/17385315

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1 year ago