Question

Simplify ((7+sin^2 theta+cos^2 theta)/(4sin^2 theta + 4cos^2 theta))

Answer 1

Answer:

2

Step-by-step explanation:

$\frac{7+sin^{2}\theta+cos^{2}\theta}{4sin^{2}\theta+4cos^{2}\theta}} = \frac{7+(sin^{2}\theta+cos^{2}\theta)}{4(sin^{2}\theta+cos^{2}\theta)}} =\frac{7+(1)}{4(1)}}=\frac{8}{4} =2$

$(sin^{2}\theta +cos^{2}\theta=1)$