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3 years ago

Hi I really need help with this & I’ll be really greatful if someone could help

Mathematics

2 answers:

antiseptic1488 [7]3 years ago

8 0

Answer:

xyz

Step-by-step explanation:

7xyz - 10 + 10 - 6xyz

-10 + 10 = 0

7xyz - 6xyz = 1xyz

1xyz = xyz

Arturiano [62]3 years ago

3 0

Answer:

xyz

Step-by-step explanation:

$7xyz - 10 + 10 - 6xyz$

$= (7xyz - 6xyz) + ( -10 + 10)$ (grouping the like terms)

$= xyz$

happy to help :)

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If a(x) = 3x + 1 and b(x)= squareroot x-4, what is the domain of (b*a)(x)?

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$\boxed{ \ x \geq 1 \ }$ or can be written as $\boxed{ \ [1, \infty) \ }$

<h3>Further explanation</h3>

This is a question about the composition of functions and how to get a domain function.

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We will form (b o a)(x) and then determine the domain.

$\boxed{ \ (b \circ a)(x) = b(a(x)) \ }$

Replace each appearance of x in b(x) with $\boxed{ \ a(x) = 3x + 1 \ }$ .

$\boxed{ \ (b \circ a)(x) = \sqrt{(3x + 1) - 4} \ }$

Thus, $\boxed{ \ (b \circ a)(x) = \sqrt{3x - 3} \ }$

To be defined, the value under the radical sign must not be negative. Therefore, the domain of $(b \circ a)(x) = \sqrt{3x - 3}$ are processed as follows.

$\boxed{ \ 3x - 3 \geq 0 \ }$

Both sides added by 3.

$\boxed{ \ 3x \geq 3 \ }$

Both sides divided by 3.

$\boxed{ \ x\geq 1 \ }$

Thus, the domain of $(b \circ a)(x) = \sqrt{3x - 3}$ is $\boxed{ \ x \geq 1 \ }$ or can be written as $\boxed{ \ [1, \infty) \ }$

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Keywords: composition of function, if a(x) = 3x + 1, and, b(x) = √(x-4), what is the domain of, (b o a)(x), b(a(x)), defined, the value, under the radical sign, must not be negative,