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kifflom [539]
3 years ago
13

How many molecules of CO2 at standard temperature and pressure in 5.4 moles of CO2

Chemistry
1 answer:
olganol [36]3 years ago
8 0

Answer:

3.25×10²⁴ molecules.

Explanation:

From the question given above, the following data were obtained:

Number of mole of CO₂ = 5.4 moles

Number of molecules of CO₂ =?

The number of molecules of CO₂ in 5.4 moles can be obtained as follow:

From Avogadro's hypothesis,

1 mole of CO₂ = 6.02×10²³ molecules

Therefore,

5.4 moles of CO₂ = 5.4 × 6.02×10²³

5.4 moles of CO₂ = 3.25×10²⁴ molecules

Thus, 5.4 moles of CO₂ contains 3.25×10²⁴ molecules.

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5.943x10^24 molecules of H3PO4 will need how many grams of Mg(OH)2 in the reaction below? 3 Mg(OH)2 + 2 H3PO4 -------> 1 Mg3(
professor190 [17]

Answer:

Mass of Mg(OH)₂ required for the reaction = 863.13 g

Explanation:

3Mg(OH)₂ + 2H₃PO₄ -------> Mg₃(PO₄)₂ + 6H₂O

(5.943 x 10²⁴) molecules of H₃PO₄ is available fore reaction. Mass of Mg(OH)₂ required for reaction.

According to Avogadro's theory, 1 mole of all substances contain (6.022 × 10²³) molecules.

This can allow us find the number of moles that (5.943 x 10²⁴) molecules of H₃PO₄ represents.

1 mole = (6.022 × 10²³) molecules.

x mole = (5.943 x 10²⁴) molecules

x = (5.943 x 10²⁴) ÷ (6.022 × 10²³)

x = 9.87 moles

From the stoichiometric balance of the reaction,

2 moles of H₃PO₄ reacts with 3 moles of Mg(OH)₂

9.87 moles of H₃PO₄ will react with y moles of Mg(OH)₂

y = (3×9.87)/2 = 14.80 moles

So, 14.8 moles of Mg(OH)₂ is required for this reaction. We them convert this to mass

Mass = (number of moles) × Molar mass

Molar mass of Mg(OH)₂ = 58.3197 g/mol

Mass of Mg(OH)₂ required for the reaction

= 14.8 × 58.3197 = 863.13 g

Hope this Helps!!!

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