W=0.360
p=1.18g/mL
pH=2.12
v=14.0 L
M(HCl)=36.46 g/mol
v₀-?
1) pH=-lg[H⁺]
[H⁺]=c(HCl)=10^(-pH)
n(HCl)=v[H⁺]=v*10^(-pH)
2) n(HCl)=m(HCl)/M(HCl)=wv₀p/M(HCl)
3) v*10^(-pH)=wv₀p/M(HCl)
v₀=v*10^(-pH)M(HCl)/(wp)
v₀=14.0*10^(2.12)*36.46/(0.360*1.18)=9.115 mL
Approximately 9.1 mL of concentrated solution required.
I think the question for this problem, is to find the capacitance. The working equation would be:
C = Q/V,
where
Q = It
Since f = 1/t, t = (1/300 kHz)(1 kHz/1,000 Hz) = 3.33×10⁻⁶ s
So,
Q = (310×10⁻⁶ A)(3.33×10⁻⁶ s)
Q = 1.033×10⁻⁹ C
Thus,
C = (1.033×10⁻⁹ C)/(3 V)
<em>C = 3.44×10⁻¹⁰ F</em>
Answer:
- be or mg
Explanation:
because of the it is easier to remove electron from the outer most shell
Answer:
option 1 pls mark bbrainliest
A habitat must include all of the following except C. More than one population of a given species.
