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Burka [1]
3 years ago
12

How many molecules of CO2 are in 132.03 grams of CO2 ?

Chemistry
1 answer:
Damm [24]3 years ago
3 0

Answer: 3.00 molecules

Explanation:

Given that:

Mass of CO2 = 132.03 grams

Number of molecules of CO2 = ?

Molar mass of CO2 = ?

For the molar mass of CO2: Atomic mass of Carbon = 12; Oxygen = 16

= 12 + (16 x 2)

= 12 + 32 = 44g/mol

Apply the formula:

number of molecules = (mass in grams/molar mass)

N = (132.03 grams/44g/mol)

N = 3.00 molecules

Thus, there are 3.00 molecules of CO2 in 132.03 grams of CO2.

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When a piece of metal is irradiated with UV radiation (λ = 162 nm), electrons are ejected with a kinetic energy of 3.54×10-19 J.
dsp73

We have that the work function of the metal

\phi=1.227*10^{-18}J

From the Question we are told that

UV radiation (λ = 162 nm)

Kinetic energy K.E =3.54*10-19 J.

Generally the equation for Kinetic energy    is mathematically given as

KE =\frac{hc}{\pi-\phi} \\\\\phi =\frac{ 6.626*10^{-34} * 3*10^8}{162*10^{-9} -3.54*10^{-19}}

\phi=1.227*10^{-18}J

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8 0
3 years ago
Write a hypothesis to predict how reaction rate will change when temperature changes. For example: “ If i heat a reaction, then
cricket20 [7]
If I heat a reaction then the rate will increase because the higher the temperature the faster the reaction.

Please vote my answer brainliest. thanks!
8 0
3 years ago
Which statement applies to electronegativity?
densk [106]

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Electronegativity is defined as the tendency of an atom to attract the shared pair of electrons towards itself whenever a bond is formed.

This property increases as we move from left to right across a period because the number of charge on the nucleus gets increased and electrons are attracted more towards the nucleus.

This property decreases as we move from top to bottom in a group because the electrons get add up in the new shells which make them further away from the nucleus.

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7 0
3 years ago
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide dissolved in molten cryolit
natka813 [3]

The given question incomplete, the complete question is:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.

Answer:

The correct answer is 6.2114 grams.

Explanation:

Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.  

Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,  

w = 27*1800*37 / 3*96500

w = 1798200 / 289500

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Hence, pure aluminum produced in the process is 6.2114 grams.  

7 0
3 years ago
Ayudameeeee Jorge AhAaaAA
Gelneren [198K]
Ok what you want. I got u
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3 years ago
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