Answer:
The area of one trapezoidal face of the figure is 2 square inches
Step-by-step explanation:
<u><em>The complete question is</em></u>
The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown. What is the area of one trapezoidal face of the figure?
we know that
The area of a trapezoid is given by the formula
where
b_1 and b-2 are the parallel sides
h is the height of the trapezoid (perpendicular distance between the parallel sides)
we have
substitute the given values in the formula
and
(f+g)(x) =
combining like terms gives you answer choice B
Answer:
Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.
Step-by-step explanation:
Remember that:
- Two lines are parallel if their slopes are equivalent.
- Two lines are perpendicular if their slopes are negative reciprocals of each other.
- And two lines are neither if neither of the two cases above apply.
So, let's find the slope of each equation.
The first basketball is modeled by:
We can convert this into slope-intercept form. Subtract 3<em>x</em> from both sides:
And divide both sides by four:
So, the slope of the first basketball is -3/4.
The second basketball is modeled by:
Again, let's convert this into slope-intercept form. Add 6<em>x</em> to both sides:
And divide both sides by negative eight:
So, the slope of the second basketball is also -3/4.
Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.
<h3>
Answer: -2/3</h3>
==================================================
Explanation:
Use the slope formula to find the slope of line E
m = (y2-y1)/(x2-x1)
m = (10-8)/(4-7)
m = 2/(-3)
m = -2/3
The slope of line E is -2/3
The slope of line F is also -2/3 since parallel lines have equal slopes but different y intercepts.
Answer:
C.) 4
Step-by-step explanation:
y2 - y1/x2 - x1
m = 160 - 80/60 - 40
m = 80/20
m = 8/2
m = 4/1
m = 4
