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miv72 [106K]
3 years ago
8

What is the right answer for this question is

Physics
1 answer:
shutvik [7]3 years ago
7 0
The answer is 3
I hope I helped
You might be interested in
A string of length L, fixed at both ends, is capable of vibrating at 309 Hz in its first harmonic. However, when a finger is pla
Scorpion4ik [409]

Answer:

 i = 0.3326 L

Explanation:

A fixed string at both ends presents a phenomenon of standing waves, two waves with the same frequency that are added together. The expression to describe these waves is

    2 L = n λ           n = 1, 2, 3…

The first harmonic or leather for n = 1

Wave speed is related to wavelength and frequency

     v = λ f

     λ = v / f

Let's replace in the first equation

    2 L = 1 (v / f₁)

For the shortest length L = L-l

   2 (L- l) = 1 (v / f₂)

These two equations form our equation system, let's eliminate v

    v = 2L f₁

    v = 2 (L-l) f₂

    2L f₁ = 2 (L-l) f₂

    L- l = L f₁ / f₂

    l = L - L f₁ / f₂

    l = L (1- f₁ / f₂)

.

Let's calculate

    l / L = (1- 309/463)

    i / L = 0.3326

4 0
3 years ago
A point charge is a model that represents a charge as acting uniformly on its surroundings. What other characteristic does a poi
inysia [295]

Explanation:

A point charge is a model that represents a charge as acting uniformly on its surroundings. The characteristics of a point charge are as follows :

  • Electric field lines are outwards if the charge is positive.
  • Electric field lines are inwards if the charge is negative.
  • If the distance from the point charge increase, the magnitude of the electric field decreases and vice versa.
3 0
3 years ago
A truck driving along a highway road has a large quantity of momentum. If it moves at the same speed but has twice as much mass,
oee [108]

If the truck moves at same speed but twice as much mass, its momentum is increased twice.

Answer:

Explanation:

Momentum is defined as the force experienced by any object for a given time. In other words, it is the measure of the mass and velocity required for a certain motion. So it is determined as the product of mass and velocity of any object.

Momentum = Mass × Velocity.

As momentum is directly proportional to both mass and velocity, increase in any one of these two quantities keeping the other constant will lead to increase in the momentum.

So in the present case, it is stated as speed is kept constant and the mass is increased twice, then the momentum will also increase twice.

New momentum = 2 ×mass × velocity = 2 × old momentum

If the truck moves at same speed but twice as much mass, its momentum is increased twice.

3 0
4 years ago
A model used for the yield y of an agricultural crop as a function of the nitrogen level n in the soil (measured in appropriate
pychu [463]

<span>The maxima of an equation can be obtained by taking the 1st derivative of the equation then equate it to 0.</span>The value of N that result in best yield is when dy/dn = 0.

Taking the 1st derivative of the equation y=(kn)/(9+n^2) :<span>
</span>

By using the quotient rule the form of the equation is:<span>
y = g(n) / h(n) 
where:</span>

g(n) = kn    --->    g'(n) = k 

<span> <span>h(n) = 9 + n^2     --->    h'(n) = 2n </span>
dy/dn is defined as:
<span>dy/dn = [h(n) * g'(n) - h'(n) * g(n)] / h(n)^2 
dy/dn = [(9 + n^2)(k) - (kn)(2n)] / (9 + n^2)^2 
dy/dn = (9k + kn^2 - 2kn^2) / (9 + n^2)^2 
dy/dn = (9k - kn^2) / (9 + n^2)^2 
dy/dn = k(9 - n^2) / (9 + n^2)^2 

<span>Equate dy/dn = 0, then solve for n 
k(9 - n^2) / (9 + n^2)^2 = 0 
k(9 - n^2) = 0 
9 - n^2 = 0 
n^2 = 9 
n = sqrt(9) 
n = 3 

<span>Answer: The nitrogen level that gives the best yield of agricultural crops is 3 units.</span></span></span></span>

5 0
3 years ago
A 1.75 kg box is pushed with a 8.35 N force across ground where k = 0.267. What is the net force on the box?
lubasha [3.4K]

The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

To find the answer, we have to know more about the basic forces acting on a body.

<h3>How to find the net force on the box?</h3>
  • Let us draw the free body diagram of the given box with the data's given in the question.
  • From the diagram, we get,

                                 N=mg\\F_t=ma\\F_t=F-f

where, N is the normal reaction, mg is the weight of the box, F_t is the net force, f is the kinetic friction.

  • We have the expression for kinetic friction as,

                      f=kN=kmg=0.267*1.75*9.8= 4.58N

  • Thus, the net force will be,

                        F_t= 8.35-4.58=3.77N

Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

Learn more about the basic forces on a body here:

brainly.com/question/28061293

#SPJ1

8 0
2 years ago
Read 2 more answers
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