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3 years ago

The area of a piston of a force pump is 8 X 10⁴m². What force must be

Physics

1 answer:

prisoha [69]3 years ago

5 0

Answer:

Force of $37.44 * 10^{8}$ Kgm/s^2 must be applied to the piston to raise oil to a height of 6.0 m

Explanation:

As we know,

Pressure is the force per unit area

Or $P = \frac{F}{A}$

Force $= P * A$

Pressure is the product of density, gravitational constant and height

$P = 780 * 10 * 6$

Force

$= P * A\\= 780 * 10*6*8*10^4\\= 37.44 * 10^{8}$ Kgm/s^2

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A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through

Neporo4naja [7]

Answer:

Explanation:

Let the charge on proton be q .

energy gain by proton in a field having potential difference of V₀

= V₀ q

Due to gain of energy , its kinetic energy becomes 1/2 m v₀²

where m is mass and v₀ is velocity of proton

V₀ q = 1/2 m v₀²

In the second case , gain of energy in electrical field

= 2 V₀q , if v be the velocity gained in the second case

2 V₀q = 1/2 m v²

1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²

mv² = 2 m v₀²

v = √2 v₀

6 0

3 years ago

Which of the following will increase the force of gravity between two charged objects without affecting the electric force?

jasenka [17]

Answer:

I believe the answer is D

Explanation:

3 0

3 years ago

The Moon orbits Earth in an average of p = 27.3 days at an average distance of a =384,000 kilometers. Using Newton’s version of

Korvikt [17]

Answer:

The mass of the earth, $M=6.023\times 10^{24}\ kg$

Explanation:

It is given that,

Time taken by the moon to orbit the earth, $T=27.3\ days=2358720\ m$

Distance between moon and the earth, $r=384000\ km=384\times 10^6\ m$

We need to find the mass of the Earth using Kepler's third law of motion as :

$T^2=\dfrac{4\pi^2}{GM}r^3$

$M=\dfrac{4\pi^2r^3}{T^2G}$

$M=\dfrac{4\pi^2\times (384\times 10^6)^3}{(2358720)^2\times 6.67\times 10^{-11}}$

$M=6.023\times 10^{24}\ kg$

So, the mass of the earth is $6.023\times 10^{24}\ kg$ . Hence, this is the required solution.

7 0

3 years ago

The energy generated by the sun travels to Earth as electromagnetic waves of varying lengths. Which statement describes an elect

Paha777 [63]

Answer: 4(45)

Explanation:

It’s not equal

3 0

2 years ago

Read 2 more answers

Hanging from a horizontal beam are nine simple pendulums of the following lengths:

LenaWriter [7]

Answer:

Options d and e

Explanation:

The pendulum which will be set in motion are those which their natural frequency is equal to the frequency of oscillation of the beam.

We can get the length of the pendulums likely to oscillate with the formula;

$L =\frac{g}{w^{2} }$

where g=9.8m/s

ω= 2rad/s to 4rad/sec

when ω= 2rad/sec

$L= \frac{9.8}{2^{2} }$

L = 2.45m

when ω= 4rad/sec

$L=\frac{9.8}{4^{2} }$

L = 9.8/16

L=0.6125m

L is between 0.6125m and 2.45m.

This means only pendulum lengths in this range will oscillate.Therefore pendulums with length 0.8m and 1.2m will be strongly set in motion.

Have a great day ahead

8 0

3 years ago