Answer:
67500 J
Explanation:
Q = mcΔt.................... Equation 1
Where Q = Amount of heat, m = mass of aluminum, c = specific heat capacity of aluminium, Δt = change or increase in temperature.
From the question,
Given: m = 1 kg, Δt = 75 °C
Constant: c = 900 J/kg.K
Substitute these values into equation 1
Q = 1×900×75
Q = 67500 J
Hence the heat energy required is 67500 J
Answer:
yes?
Explanation:
I don’t really understand your question
<h3><u>Answer;</u></h3>
<em>Producers </em>
<h3><u>Explanation;</u></h3>
- <u><em>Producers </em></u>occupy the lowest level in any food chain or food web. They are the organisms that all other organisms in the food chain rely on.
- <em><u>Producers </u></em>have the ability to make their own food through the process of photosynthesis where they use energy from sunlight, together with water and carbon dioxide to generate food.
- The ability of producers to make their own food and the fact that they occupy the lowest level in a food chain means <em><u>they have the highest biomass.</u></em>
Answer:
power = 23.2 mW
Explanation:
given data
resister r = 5.80 kΩ
current measures I1 = 3.10 m A
measure current I2 = 1.10mA
solution
we get here I total
I = current 1 - current 2
I = 3.10 - 1.10
I = 2 mA
so here power will be
power = I²×R .............1
power = 2² × 5.80
power = 23.2 mW
Answer:
t = 2s
Explanation:
When you're looking for instantaneous portions of a graph, of any sort really, it means you're observing a rate at a single point in time [or possibly some other variable]. It's sorta like a snapshot of a rate as opposed to an average rate over an interval. After choosing this rate we'll typically draw a straight, tangent line through it to indicate it's slope. (Tangent lines are just lines that only touch a single point on a graph or shape.)
Another thing to take note of are the values of the graph's major axes. The "y-axis" corresponds to velocity in meters per second, while the "x-axis" corresponds to time in seconds. Normally when relating the two we put "y" over the "x" and say that at any point there are "y[units]" per "x[units]". Though with instantaneous rates, we say the value of "x" is "1"; for reasons I can try to further explain later if you'd like.
With the above information in mind we can turn our attention to your graph. You're told to find the point on this graph where the instantaneous rate of acceleration is -2 m/s². The only place where the graph reflects an instantaneous rate of -2m/s² is at t = 2s. At t = 2, the rate comes out to (2[m/s]/1s), which simplifies to 2m/s². If you then draw the tangent line through the point, you'll find that the line is decreasing (going down from left to right) which means that the instantaneous rate is negative.
So at t = 2s, we have an instantaneous acceleration of -2m/s².
