Answer:
1250 J
Explanation:
KE = 1/2(100 kg)(5 m/s)^2
KE = 1250 J
The mass of a 4,900 newtons bobsled is 500 kilograms.
The frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.
<h3>
Frequency detected by the student</h3>
The observed frequency is determined by applying Doppler effect;
f' = f₀(v + v₀)/(v)
where;
- f' is the observed frequency
- v is speed of sound
- v₀ is the source speed
- f₀ is the original frequency
f' = 342(6 + 336)/(336)
f' = 348.1 Hz
Thus, the frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.
Learn more about observed frequency here: brainly.com/question/10728818
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The Modem
or physically connecting on the computer the data port is for a cable to connect
<span>Assume: neglect of the collar dimensions.
Ď_h=(P*r)/t=(5*125)/8=78.125 MPa ,Ď_a=Ď_h/2=39 MPa
τ=(S*Q)/(I*b)=(40*〖10〗^3*π(〖0.125〗^2-〖0.117〗^2 )*121*〖10〗^(-3))/(π/2 (〖0.125〗^4-〖0.117〗^4 )*8*〖10〗^(-3) )=41.277 MPa
@ Point K:
Ď_z=(+M*c)/I=(40*0.6*121*〖10〗^(-3))/(8.914*〖10〗^(-5) )=32.6 MPa
Using Mohr Circle:
Ď_max=(Ď_h+Ď_a)/2+âš(Ď„^2+((Ď_h-Ď_a)/2)^2 )
Ď_max=104.2 MPa, Ď„_max=45.62 MPa</span>
