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lidiya [134]
3 years ago
13

(4,-1)&(6,2) what is the slope

Mathematics
1 answer:
DedPeter [7]3 years ago
3 0

Answer:

m=\frac{3}{2}

Step-by-step explanation:

<u>Step 1:  Find the slope</u>

<u />m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{2-(-1)}{6-4}

m=\frac{3}{2}

Answer:  m=\frac{3}{2}

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EXPERTS/ACE PLEASE HELP!!
Zielflug [23.3K]
Hey!! I'm not Expert/Ace, but I am a Virtuoso so I hope I can help :p

Braden bought 18 pencils for $4.50
The number of pencils bought is x, and total cost is y.
x = 18      y = 4.5 
you would then plot the point (18, 4.5).
I am assuming that because you need a line, I will need to make another pencils bought/price. 
The point I made is (30, 7.5).
(You can get another point by dividing 4.5 by 18, and then using the result, .25 to see how much it would cost to by x amount of pencils.) 
Attached is the line I got by plotting both points, and connecting them :)
I hope I answered your question!!

5 0
3 years ago
A hiker at the top of a mountain spots his car back in the parking lot at the
mart [117]
<h2>Answer:</h2><h2>The angle of depression from the hiker to his car, Θ = 56.39 degrees</h2>

Step-by-step explanation:

A hiker at the top of a mountain spots his car back in the parking lot at the

bottom of the trail.  If the trail is 632 meters long and the mountain is 420

meters tall,

opposite side = 632 m

adjacent side = 420 m

Angle of depression, Θ = arctan (\frac{opposite}{adjacent} )

= arctan (\frac{632}{420} )

Θ = 56.39 degrees

3 0
4 years ago
The breaking strengths of cables produced by a certain manufacturer have a mean, , of pounds, and a standard deviation of pounds
olchik [2.2K]

The question is incomplete. The complete question is :

The breaking strengths of cables produced by a certain manufacturer have a mean of 1900 pounds, and a standard deviation of 65 pounds. It is claimed that an improvement in the manufacturing process has increased the mean breaking strength. To evaluate this claim, 150 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1902 pounds. Assume that the population is normally distributed. Can we support, at the 0.01 level of significance, the claim that the mean breaking strength has increased?

Solution :

Given data :

Mean, μ = 1900

Standard deviation, σ = 65

Sample size, n = 150

Sample mean, $\overline x$ = 1902

Level of significance = 0.01

The hypothesis are :

$H_0 : \mu = 1900$

$H_1 : \mu > 1900$

Test statics :

We use the z test as the sample size is large and we know the population standard deviation.

$z=\frac{\overline x - \mu}{\sigma / \sqrt{n}}$

$z=\frac{1902-1900}{65 / \sqrt{150}}$

$z=\frac{2}{5.30723}$

$z=0.38$

Finding the p-value:

P-value = P(Z > z)

             = P(Z > 0.38)

             = 1 - P(Z < 0.38)

From the z table. we get

P(Z < 0.38) = 0.6480

Therefore,

P-value = 1 - P(Z < 0.38)

            = 1 - 0.6480

             = 0.3520

Decision :

If the p value is less than 0.01, then we reject the H_0, otherwise we fail to reject  H_0.

Since the value of p = 0.3520 > 0.01, the level of significance, then we fail to reject  H_0.

Conclusion :

At a significance level of 0.01, we have no sufficient evidence to support that the mean breaking strength has increased.

4 0
3 years ago
Kevin bought 4/6 pounds of pecans for $50.89. About how much was the cost per pound?
sukhopar [10]

Answer:

$76.33

Step-by-step explanation

1 divided by 4/6 = 3/2 =1.5

50.89 x 1.5 =$76.33

5 0
4 years ago
What are the restrictions for (x^2+10x+25)/(x^2-3x-28)<br><br> 0,14<br> -4,7<br> 0,7<br> 4,7
nirvana33 [79]
The answer is -4,7

The denominator can't equal zero. Factor the denominator:
x^2 - 3x - 28=
(X - 7)(x + 4); next set each set of parentheses equal to 0;
x - 7 = 0; so x=7 is one value
x + 4 = 0; so x=-4 is the other
Remember, x = 7 and x= -4 make the denominator zero, which is a "restriction" because you can't divide by zero.
5 0
4 years ago
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