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Alik [6]
2 years ago
12

Evan has x pennies and y nickels. He has no less than 20 coins worth no more than $0.75 combined. Solve thus system of inequalit

ies graphically and determine onr possible solution
Mathematics
1 answer:
Lana71 [14]2 years ago
5 0

Answer:

x = 12, y = 10

Step-by-step explanation:

Given that:

Number of pennies = x

Total amount in pennies = x cents

Number of nickels = y

Total amount in nickels = 5y cents

Number of coins are not less than 20.

i.e. the inequality can be written as:

x+y>20 .... (1)

Total money is not more than $0.75 i.e. 75 cents

The inequality can be written as:

x+5y ...... (2)

Also, the number of nickels and pennies must be in positive numbers.

Therefore,  

x > 0 ...... (3)\\y > 0 ....... (4)

When plotted in graph, we get the image as attached in the answer area.

Solution of the graph is the area which is common to both the lines.

And one solution between them is (12, 10)

i.e. number of pennies, x = 12

Number of nickels, y = 10

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Choose the correct option that explains what steps were followed to obtain the system of equations below
Dominik [7]

Answer:

option C is the correct answer

Step-by-step explanation:

System A:                                                  System B:

-x - 2y = 7    ........(1)                               -x - 2y = 7    .......(3)  

5x - 6y = -3  ........(2)                                  -16y= 32  ........(4)

Solution for system A: ( -3, -2)

For option A

Multiply the first equation by 3

3(- x - 2y) = 3(7)         ⇒     - 3x - 6y = 21 ........... (5)

Add equation 2 and 5

  5x - 6y = -3

<u> - 3x - 6y = 21</u>

  2x -12y = 18   ⇒  2( x - 6y ) = 2( 9 )    ⇒   x - 6y = 9

Option A is not equal to equation in system B so now we check option B.

 For option B

Multiply the first equation by -5

-5(- x - 2y) = -5(7)         ⇒    5x + 10y = -35 ........... (6)

Add equation 2 and 6

  5x - 6y = -3

<u>   5x + 10y = -35</u>

  10x + 4y = -38   ⇒   2( 5x + 2y ) = 2(-19)    ⇒  5x + 2y = -19

Option B is not equal to equation in system B so now we check option C.

For option C

Multiply the first equation by 5            

5(- x - 2y) = 5(7)         ⇒   - 5x - 10y = 35 ........... (7)

Add equation 2 and 7

  5x - 6y = -3

<u> - 5x - 10y = 35</u>

    0 - 16y = 32   ⇒   -16y = 32

Option C is equal to equation in system b so now we check if the solution to system B is same as system A.  

Solution to system B:

First, we find value of y from equation 4:

-16y = 32   ⇒    y = \frac{32}{-16}   ⇒    y = -2

Now, we put value of y in equation 3 to find value of x:

-x - 2y = 7  ⇒  -x - 2(-2) = 7   ⇒  -x + 4 = 7   ⇒  -x = 7 - 4  ⇒  -x = 3

multiply both sides by -1

-1 × (-x) = -1 × (3)       ⇒     x = -3

Solution of system B = (-3, -2)

Solution of system B is the same as system A, so option C is correct.

6 0
3 years ago
Read 2 more answers
A car traveling at constant speed traveled 262.5 miles in 3 1⁄2 hours. What was the car's speed?
CaHeK987 [17]
S= 262.5÷ 3.5 = 75 mph
5 0
3 years ago
Read 2 more answers
What is the value of 10x+1 3
Veseljchak [2.6K]

SOLUTION

In this question, we are meant to expand the expression:

(10x+1)^{3\text{ }}\text{ = ( 10 x + 1 ) (10 x + 1 ) ( 10 x + 1 )}\begin{gathered} (10x+1)(10x+1)=100^{}x^2\text{ + 20 x + 1} \\ \text{Then,} \\ (100x^2+20x+1)(10x+1)=1000x^{3\text{ }}+200x^2+10x+100x^2\text{ + 20 x + 1} \\ \text{ = 1000 x}^{3\text{ }}\text{ + }300x^2\text{ + 30 x + 1} \\  \\ \text{CONCLUSION: ( 10 x + 1 )}^{3\text{ }}=1000x^{3\text{ }}+300x^2\text{ + 30 x +1} \end{gathered}

7 0
1 year ago
PLEASE HELP!
leva [86]

Answer:

B. 56°

Step-by-step explanation:

We are given that m∠R is 66° and m∠T is 122°.

We can apply the supplementary rule since ∠S and ∠T are a linear pair. So, we can use ∠T to find ∠S through 180° - 122° = 58°.

Now, we can use ∠R and ∠S to find ∠Q.

66° + 58° = 124°

180° - 124° = 56°

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2 years ago
What is the area of the kite?<br> 6 ft<br> 14 ft
Dovator [93]

Answer:

Step-by-step explanation:

if these are diagonals ,then

area=(product of diagonals)/2

=(6*14)/2=42 ft²

4 0
2 years ago
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