Answer:
L= 1.468 m
Explanation:
The moment of inertia of the rod about its center is (1/12)m_RL^2
The moment of inertia of each of the two bodies about the described axes is m_B(L/2)2
Hence, the moment of inertia of three body system is (1/12)m_RL^2+ 2×m_B(L/2)^2 which is given to be equal to I_T
=> L^2[(1/12)m_R+m_B/2] = I_T
=> L2 = IT/(mR/12+ mB/2)
=> L = sqrt( 12I_T/(m_R+6m_B))
now putting the value of m_R= 3.47 kg
m_B= 0.263 kg
I_T = 0.97 kg/m^2
L= 1.468 m is the length of the rod be so that the moment of inertia of the three-body system
-3.5912m/s^2Use vf^2 = vi^2 + 2ax in your calculations, knowing vf, vi, and x.
Answer: The law of conservation of energy is a physical law that states energy cannot be created or destroyed but may be changed from one form to another. Another way of stating this law of chemistry is to say the total energy of an isolated system.
Explanation: