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kotykmax [81]
3 years ago
7

How much work is done if a 50N weight is lifted to a height of 10m? ​

Physics
1 answer:
borishaifa [10]3 years ago
6 0

500J  

Explanation:

Given parameters:

Weight of the body = 50N

Height = 10m

Unknown:

Work done = ?

Solution;

Work done is the force that moves a body through a particular distance in the direction of the force.

In this problem, we can solve the problem by relating work done to the potential energy used in lifting the mass.

  The weight on a body, a force in the presence of gravity

         weight(weight) = mg

  where m = mass of body

              g = acceleration due to gravity

  Work done = Fxd

   Where F = force on the body

               d = distance moved

Potential energy = mgh

    where h is the height

     P.E = work done =  Weight x height = 50 x 10 = 500J  

Learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

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kykrilka [37]

The average radius(r) of each grain is r = 50 nanometers = 50*10^-6 meters

Since it is spherical, so

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V= (4/3)*pi*(50*10^-6)^3

V=5.23599*10^-13 m^3

 

We are given the Density(ρ) =2600kg/m^3

 

We know that:

Density(p) = mass(m)/volume(V)

m = ρV

 

So the mass of a single grain is:

m = 5.23599*10^-13 * 2600 = 1.361357*10^-9 kg

 

 

The surface area of a grain is:

a = 4*pi*r^2

a = 4*pi*(50*10^-6)^2

a = 3.14*10^-8 m^2

 

 

Since we know the surface area and mass of a grain, the conversion factor is:

1.361357*10^-9 kg / 3.14*10^-8 m^2

 

Find the Surface area of the cube:

cube = 6a^2

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multiply this by the converions ratio to get:

total mass of sand grains = (7.26 m^2 * 1.361357*10^-9 kg) / (3.14*10^-8 m^2)

total mass of sand grains = 0.3148 kg = 314.80 g

3 0
3 years ago
What is the strength of the electric field in a region where the electric potential is constant?
Roman55 [17]

Answer:

Where the electric potential is constant, the strength of the electric field is zero.

Explanation:

As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e

Eₓ = - dV / dx        ----------(i)

From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.

<em>Therefore, a constant electric potential means that electric field is zero.</em>

4 0
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To demonstrate the tremendous acceleration of a top fuel drag racer, you attempt to run your car into the back of a dragster tha
Daniel [21]

Answer:

Explanation:

If the dragster  attains the speed equal to that of the car which is moving with constant velocity of v₀ , before the two close in contact with each othe , there will not be collision .

So the dragster starting from rest , must attain the velocity v₀ in the maximum time given that is tmax .

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Answer:

Explanation:

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Answer:

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The minimum amount of energy required by a metal surface to eject an electron from its surface is called work function of metal surface.

The electrons thus emitted are called photo-electrons.

The current produced as a result is called photo electricity.

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8 0
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