Is the relation shown in the table a function? <br><br> Yes <br><br> No

What fractions are equal to 17.09 repeating

Katen [24]

17.09 has 2 decimal places, so we put the decimal digits of 17.09, 09, over 1 followed by the number of zeroes equal to the number of decimal places, 2: 09 = 09/100. We add 17 as 1700/100 and get: 17.09 as decimal fraction = 1709/100

5 0

3 years ago

A random number generator chooses 2 numbers between 1 and 5 what is the probability that the computer will pick 1 and 2

Verdich [7]

$|\Omega|=\binom{5}{2}=\dfrac{5!}{2!3!}=\dfrac{4\cdot5}{2}=10\\
|A|=1\\\\
P(A)=\dfrac{1}{10}=10\%$

6 0

4 years ago

my company wants to produce 2234 models each day. one employee can make a single model car in 5 minutes. we work 6 hours a day.

valentinak56 [21]

Answer:

The Answer IS 32 Employees

Step-by-step explanation:

No of cars produced in an Hour = 12 Cars

No or cars produced in a day by one employee = 12*6 = 72

No of employees needed = 2234 / 72 = 31.02

= 32 Employees

(Note that the 0.02 petcent notes for some cars so we need another employee)

Mark Brainliest PWEESE

6 0

2 years ago

Please tell me the value of each number in the number 457.37

kkurt [141]

Answer:

4 = hundreds (400), 5 = tens (50), 7 = ones (7),

- AFTER DECIMAL - 3 = tenths (0.3) 7 = hundredths (0.07)

Step-by-step explanation:

Hope this helps

Give brainiest if it did

6 0

3 years ago

A shoe manufacturer was investigating the weights of men's soccer cleats. He felt that the weight of these cleats was less than

aleksklad [387]

Answer:

The conclusion is that the researcher was correct

Step-by-step explanation:

From the question we are told that

The sample size is $n = 13$

The sample mean is $\= x = 9.63$

The standard deviation is $s = 0.585$

The significance level is $\alpha = 0.05$

The Null Hypothesis is $H_o : \mu = 0$

The Alternative Hypothesis is $H_a = \mu < 10$

The test statistic is mathematically represented as

$t = \frac{\= x - \mu }{\frac{s}{\sqrt{n} } }$

Substituting values

$t = \frac{9.63 - 10 }{\frac{0.585}{\sqrt{13} } }$

$t = - 2.280$

Now the critical value for $\alpha$ is

$t_{\alpha } = 1.645$

This obtained from the critical value table

So comparing the critical value of alpha and the test value we see that the test value is less than the critical value so the Null Hypothesis is rejected

The conclusion is that the researcher was correct

6 0

4 years ago

Is the relation shown in the table a function? Yes No