Aldehydes and ketones having
α-hydrogen atoms, undergoes aldol condensation, in present of base (NaOH).
The initial product formed during this reaction is
β-hydroxy alcohol, which then undergoes dehydration to form
α,β-unsaturated aldehyde or ketone.
In present case, 3,3-dimethyl-2-butanone has 2α-hyrogen atom, while methylcyclopentane-1-carbaldehyde has 1α-hydrogen atom. So the major product formed during cross aldol condensation reaction of these reactants is:
5-hydroxy-4,4-dimethly-1-(2-methylcyclopentyl)pent-1-en-3-one. The complete reaction product formed is shown below.
Atoms cannot be created or destroyed by chemical reactions. They just have a some bonds rearranged is all.
Answer:
N2C14
Explanation:
<em> determined the bond type by looking if it is a metal or nometal</em>
<em>Ionic Bond:NM+M</em>
<em>Covalent Bond:NM+NM</em>
You're going to divide the mass of chlorine within the compound by the mass of the compound, and then multiply the result by 100 to get the answer
Beef and cheddar I believe!!!