The coordinates of the vertices of the triangle are
(–8, 8), (–8, –4), and<span> (10, –4)</span>.
Consider QR the base of the triangle. The measure of the base is b = 18 units, and the measure of the height is h = <span>12</span> units.
The area of triangle PQR is<span>108</span> square units.
Answer:
Below
Step-by-step explanation:
To find the rate we have to divide
2/3=.67
then we can multiply all the numbers by .67
1=.67
2=1.34
5=3.35
10=6.7
Desmos is hard sometimes :)
To solve this problem, we must imagine the triangles and
parallel lines which are formed. It is best to draw the triangle described in
the problem so that you can clearly understand what I will be talking about.
The first step we have to do is to make an equality equation
in triangle ABC.
In triangle ABC, we are given that lines XY and BC are two
parallel lines (XY || BC). Therefore
this means that:
AX / XB = AY / YC --->
1
The next step is to make an equality equation in triangle
AXC.
We are given that lines ZY and XC are two parallel lines (ZY
|| XC). Therefore this also means that:
AZ / ZX = AY / YC ---> 2
Combining 1 and 2 since they have both AY / YC in common:
AX / XB = AZ / ZX
we are given that:
AZ = 8, ZX = 4 therefore AX = AZ + ZX = 12, hence
12 / XB = 8 / 4
XB = 6
Answer:
x^2 - 3x - 28
Step-by-step explanation:
(x+4)(x-7)
x^2-7x+4x-28
