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Nookie1986 [14]
3 years ago
5

Solve for x

2%20%20%7B%7D%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20" id="TexFormula1" title="8 {}^{2 + x} + 2 {}^{3x} = 32 {}^{ \frac{1}{2} } " alt="8 {}^{2 + x} + 2 {}^{3x} = 32 {}^{ \frac{1}{2} } " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Stella [2.4K]3 years ago
7 0

Answer:

8^2+x + 2^ 3x = 32^ 1/2

2^3(2+x) + 2^3x = 2^5^1/2

All two's will cancel out

3(2+x) + 3x = 5^1/2

6+3x + 3x = 5^1/2

6 +6x = 2.23

6x = 2.23 - 6

6x = -3.77

x = -3.77÷ 6

x = -0.63

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You will have a 3:6 probability of getting an even number
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The sum of the angle measures of a polygon with s sides is 2880. Find s. A. 20 B. 16 C. 17 D. 18
siniylev [52]
I think the answer is D. 18

8 0
3 years ago
..1+4=5. 2+5=12. 3+6=21. 8+11=40 or this could be 96 which is right and why
andre [41]
Multiply the numbers being added then add the first number. 4X1=4, 4+1=5.
2X5=10, 10+2=12. 11X8=88, 88+8=96. I'm not sure how to get 40, though. 
Hope I could help.
7 0
2 years ago
A rectangular shoebox has a volume of 728 cubic inches.the base of the shoebox measures 8 inches by 6.5 inches.how long is the s
Flauer [41]

Answer:the answer is 14

Step-by-step explanation: first you want to multiply

8*6.5

=52

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728/52

14

hope this helps

Goog luck!

5 0
3 years ago
I need the answer for this problem please
Savatey [412]

Answer:

B

Step-by-step explanation:

Find all probabilities:

A. False

Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}

B. True

Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}

C. False

Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}

D. False

Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}

4 0
3 years ago
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