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Ad libitum [116K]
3 years ago
14

Estimate the following product in scientific notation, and then select best answer for the products power of 10.

Mathematics
1 answer:
MaRussiya [10]3 years ago
5 0
It’s 15 I know this.......
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Solve xy - 3 = k solve for x
ladessa [460]

Answer:

x=(k+3)/y

Step-by-step explanation

First, we simplify by adding 3 to both sides of the equation

xy-3+3=k+3

Now it's xy=k+3

To get x we divide both sides by y

So x=(k+3)/y

3 0
3 years ago
Read 2 more answers
The area of trapezium is 1586cm² and the distance between sides is 26cm.If one of the parallel sides is 84cm,find the other​
irinina [24]

Check the picture below.

we know the area is 1586, so

\stackrel{\textit{area of a trapezoid}}{A=\cfrac{h(a+b)}{2}}\implies 1586=\cfrac{26(84+b)}{2}\implies 1586=13(84+b) \\\\\\ \cfrac{1586}{13}=84+b\implies 122=84+b\implies 38=b

3 0
2 years ago
A ball is thrown from an initial height of 2 feet with an initial upward velocity of 29 ft/s. The balls height (h) [in feet] aft
nirvana33 [79]
The ball is at a height of 14 feet after 1.17 and 0.64 seconds.

This is an example of a quadratic equation. Write out the equation with 14 in the place of the height. Then, set it equal to zero.

14 = 2 + 29t - 16t^2

0 = -16t^2 + 29t -12

Now, we can use the quadratic equation to solve.
A = -16
B = 29
C = -12

You will get the solutions of 1.17 and 0.64.
5 0
3 years ago
What is the area of this trapezoid with height 13 units? Please put correct answer
Dmitry [639]

Yo sup??

area of trapezium=1/2*sum of opposite sides* height of trapezium

=1/2*44*13

=22*13

=286 sq units

Hope this helps

7 0
3 years ago
Read 2 more answers
Jammal makes a cut through a block of florist's foam, as shown. What are the dimensions of the exposed cross section?
Ahat [919]

Answer:

C. 3 in x 6 in

Step-by-step explanation:

Jammal cuts the block in a straight line parallel to one side... so the section revealed when he finishes his cut will be identical as the parallel side to which the cut is done.

We know the the left side of the prism on the image is 3 inches wide and 6 inches high... so that will also be the dimensions of the exposed cross section.

The answer is then 3 inches y 6 inches. The thickness of the block (5 inches) has no impact on the exposed area of the cross-section.

8 0
4 years ago
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