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ozzi
3 years ago
13

A binomial consists of how many terms

Mathematics
1 answer:
patriot [66]3 years ago
5 0
2 because “bi” means 2
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Steven wishes to save for his retirement by depositing $2,000 at the beginning of each year for thirty years. Exactly one year a
Ad libitum [116K]

Step-by-step explanation:

i = interest 3% for 30 years

This is a simple dynamical system for whom the the solutions are given as

S=R[\frac{(i+1)^n-1}{i}](i+1)

putting values we get

S=2000[\frac{(1.03)^{30}-1}{0.03}](1.03)

= $98005.35

withdrawal of money takes place from one year after last payment

To determine the result we use the present value formula of an annuity date

P = R\frac{1-(1+i)^{-n}}{i}{i+1}

we need to calculate R so putting the values and solving for R we get

R= $6542.2356

8 0
3 years ago
Solve for s.<br> S + 3s - 4 = 16<br> S =<br> Submit
const2013 [10]
The answer is 5 because 16+4=20 and 3s + s = 4s so you’re left with 4s = 20 and I know that 4 times 5 is 20.
ANSWER: S=5
3 0
3 years ago
Doug is in line at the store. He has three items that cost ​$4.50​, ​$3.05​, and ​$1.50. Explain how Doug can add the cost of th
Angelina_Jolie [31]

Answer:

He can add through calculater or by doing addition in his mind

4 0
3 years ago
Read 2 more answers
Express the form 1: n <br><br> 5:20
Stella [2.4K]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

5 : 20

Divide both sides by 5 to get the answer

5/5 = 1

20/5 = 4

Thus, the answer is 1 : 4

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

8 0
3 years ago
Please Help Me! It’s Math! Please!
nadezda [96]

Answer:

D. About 800 years

Step-by-step explanation:

Use the half-life equation:

A = A₀ (½)ⁿ

where A is the final amount,

A₀ is the initial amount,

and n is the number of half-lives.

0.90A₀ = A₀ (½)ⁿ

0.90 = (½)ⁿ

To solve for n, take log of both sides:

log 0.9 = n log 0.5

n = (log 0.9) / (log 0.5)

n = 0.152

It takes 0.152 half-lives.  The half-life of carbon-14 is 5730 years.

0.152 × 5730 years = 871 years

The closest answer is D.

8 0
3 years ago
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