All categories

3 years ago

Find the value of x.

Mathematics

1 answer:

Gemiola [76]3 years ago

3 0

Answer:

Step-by-step explanation:

Hope this helps!

You might be interested in

Which equation has only one solution?

sveticcg [70]

A because only 6-5 = -1

7 0

3 years ago

At the beginning of year 1, Gracie invests $350 at an annual simple interest rate of 4%. She makes no deposits to or withdrawals

scZoUnD [109]

Answer:

Step-by-step explanation:

The answer is A

5 0

3 years ago

Ivan chases a goat for 41 seconds. He runs at 7 meters per second.<br> How far does he go?

andre [41]

If he runs 7 meters per second for 41 seconds, then his total distance is 41 x 7, which is 287 meters

4 0

3 years ago

Read 2 more answers

Sarah is making flower bouquets that she will put in 10 vases. She will put 15 roses and some lilies in each vase.

AnnyKZ [126]

A is correct because the f represents the lilies and then you add the 15 because that is how much roses there are going to be. Lastly just multiply the ten that will give you the answer

3 0

3 years ago

Which statement about sqrt x-5 minus sqrt x=5 true?

Allushta [10]

Answer:

9 is an extraneous solution.

Step-by-step explanation:

Extraneous solution is a solution that when plugged into the equation do not hold true.

Here we are given an algebraic equation in terms of single variable x as:

$\sqrt{x-5}-\sqrt{x}=5-----(1)$

Now, we will solve this equation to obtain the solution as:

on squaring both side of the equation we obtain:

$(\sqrt{x-5}-\sqrt{x})^2=5^2$

$x-5+x-2\sqrt{x-5}\sqrt{x}=25\\\\2x-5-2\sqrt{x-5}\sqrt{x}=25\\\\2x-30=2\sqrt{x-5}\sqrt{x}\\\\on\ dividing\ both\ side\ by\ 2\ we\ obtain:\\\\x-15=\sqrt{x-5}\sqrt{x}$

Again on squaring both side of the equation we obtain:

$x^2+225-30x=(x-5)x\\\\\x^2+225-30x=x^2-5x\\\\225=-5x+30x\\\\225=25x\\\\x=9$

Now when we plug x=9 back to the original equation i.e. equation (1) we get:

$\sqrt{9-5}-\sqrt{9}=5\\\\\sqrt{4}-\sqrt{9}=5\\\\2-3=5\\\\-1=5$

Hence, the equation does not hold true.

Hence, 9 is a extraneous solution

5 0

3 years ago