You can see that if the small rectangle is 2/3 of the big triangle by the 4 and 6 that it gives you. If you divide 10 by 2 and multiply it by 3, you get the answer you need. which is 15.
Answer:
13
Step-by-step explanation:
using BODMAS
13-11=2
SO 2*2=4
4/4=1
1*72=72
THEREFORE it is 85-72 =13
As the question say this problem is a practice of the law of cosines!
The law of cosine: c^2=a^2+b^2-2ab*cos*c for any side a, b and c
The law can also be written as c=sqrt(a^2+b^2-2abcosc)
Now use this formula!(note cos 100 degrees is about 0.8623)
c=sqrt(15^2+16^2-2*15*16*cos100)
solving this we can MN is about 23.75
Round this to the nearest tenths now!
We get 23.8!
Thus the answer is D
Answer:
x= -23
Step-by-step explanation:
-×= 46-23
-×=23
-×/-1=23/-1
x=-23
x = 6.03 seconds
Step-by-step explanation:
The equation of motion of the rocket is
y = -16x^2 + 193x + 128
We can determine its maximum height ymax when its vertical velocity y' reaches zero. Taking the derivative of y, we get
y' = -32x + 193
The value nen of x that makes y' will give us the time needed by the rocket to reach its maximum height ymax. So setting y' = 0 we get
x = 193/32 = 6.03 second
Bonus:
Putting this value of x into y, we'll get
y(x = 0.59s) = -(16 ft/s^2)(6.03 s)^2 + (193 m/s)(6.03 s) + 128 ft
= 710 ft
