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zimovet [89]
3 years ago
9

Which expressions are equivalent to 35+30s−45t I need three

Mathematics
2 answers:
Volgvan3 years ago
8 0

Answer:

5(7+6s-9t), (70+60s-90)/2, and (105+90s)/3-45

ratelena [41]3 years ago
7 0

Answer:

Step-by-step explanation:

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The radius of a circle measures 5 inches A central angle of the circle measuring 12 radians cuts off a sector
blagie [28]

Answer:

  25/4 square inches

Step-by-step explanation:

The area of a sector of a circle is given by the formula ...

  A = (1/2)r²θ

where r is the radius and θ is the central angle in radians.

For your sector, the area is ...

  A = (1/2)(5 in)²(1/2) = 25/4 in²

8 0
3 years ago
PLEASE ANSWER QUICK!!!SHOW STEPS
Vedmedyk [2.9K]
5. Given the equation y = (1/4) cos[(2pi/3)*theta]:
5a. For the general equation y = a cos(bx), the period is given by 2pi/b. In this equation, b = 2pi/3, so this means that 2pi/b = 2pi/(2pi/3) = 3. Therefore, the period of this equation is 3, and the cosine wave repeats itself every 3 x-units.
5b. For the general equation y = a cos(bx), the amplitude is given by a. Therefore the amplitude is a = 1/4, and this means that the cosine wave's range is from -1/4 to 1/4 for all values of x.
5c. The equation of the midline is y = 0. This represents the average value over the wave. This is determined by adding the highest and lowest values of the range and taking the average, in this case, 1/4 + (-1/4) = 0, and 0 / 2 = 0. Another way to do this is using the general equation y = a cos(bx) + c, where the midline's equation is y = c. In this case, there is no value of c in the given, implying that c = 0, and the midline is y = 0.

6. Let the horizontal distance be x. Then tan42 = h/x, and h = x tan42. Then using the Pythagorean theorem: 3280^2 = h^2 + x^2
3280^2 = x^2 (tan42)^2 + x^2
3280^2 = x^2 [(tan42)^2 + 1]
x = 2437.52
Therefore, h = x tan42 = 2,194.75 ft.

5 0
3 years ago
Read 2 more answers
The lines s and t intersect at point R.
natka813 [3]

Answer:

61

Step-by-step explanation:

79 + 40 = 119

180 - 119 = 61

8 0
3 years ago
Read 2 more answers
Complete the function table below for the function F(x) = x2 + 1.
VMariaS [17]
The answer is true, and let me explain this to you like this:
<span>F(x) = 4x - 6
when x = 1, F(x) = 4 * 1 - 6 = -2
when x = 2, F(x) = 4 * 2 - 6 = 2
when x = 3, F(x) = 4 * 3 - 6 = 6
when x = 4, F(x) = 4 * 4 - 6 = 10
</span><span>second row is: -2, 2, 6, 10
</span><span>differences are: 2 - (-2) = 4; 6 - 2 = 4; 10 - 6 = 4
</span>So, the <span>second row is in arithmetic progression.
Hope this is what you were looking for</span>
5 0
3 years ago
Read 2 more answers
Write the point slope form of the equation of the line using the point (-4,-2)
Gre4nikov [31]

Answer:

y + 2 = \frac{5}{4} (x + 4)

Step-by-step explanation:

1) First, find the slope of the line. Take two points the line intersects and use them for the slope formula, \frac{y_2-y_1}{x_2-x_1}. We already know the line intersects (-4, -2). Just choose any one of the points you can see the line intersecting (in this case, I chose (0,3)) and plug in its values, too. Then solve:

\frac{(3)-(-2)}{(0)-(-4)} \\\frac{3+2}{0+4} \\\frac{5}{4}

So, the slope is \frac{5}{4}.

2) Now that you have the slope, plug in values for the point-slope formula, y - y_1 = m (x - x_1). In order to write a linear equation with it, the x_1, y_1, and m have to be substituted for with real values. The m represents the slope - which means that we should place \frac{5}{4} there. The x_1 and y_1 represent the x and y values of a point - and the questions wants us to use (-4, -2), so substitute -4 for x_1 and -2 for y_1:

y-(-2) = \frac{5}{4} (x - (-4))\\y + 2 = \frac{5}{4} (x + 4)\\

Thus, the answer is y + 2 = \frac{5}{4} (x + 4).

8 0
3 years ago
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