Answer:
f(x)=x^2+3
f(x+y)=(x+y)^2+3
this is done by replacing x with (x+y)
f(x+y)=x^2+2xy+y^2+3
therefore : f(x+y)= x^2+y^2+2xy+3
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The probability of getting 0 heads in 4 tosses (or equivalently, 4 tails) is
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.
So the desired probability is
Cone volume formula: V = πr²h/3
r = radius
h = height
The radius is half the diameter, so, we can divide.
2 / 2 = 1
Now, solve with the given values.
V = π(1)²(1)/3
V = π(1)(1/3)
V = 3.14(1/3)
V ≈ 1.05
Therefore, the volume is roughly 1.05m^3
Best of Luck!
Answer:
x+x=2x
Step-by-step explanation: