In the instructions for this problem I am told to distribute -4x^2. Why?
the order of operations is the order in which to simlify
if you look inside the parenthases, all like terms have been combined so the inside of parenthasees have already been simlified
expanding the exponents won't make it any easier so we move to distriubiting (or mulitplying)
so then the next step is mulitply -4x^2 by the trinomial
<span>In
the order of operations you must do problems inside parentheses first.
Why does multiplying monomials by polynomials change this? </span>multiplying monomails by polynomials does not change this
<span>Would the answer come out different if I did the work according to the order of operations?
no because distributing first is what you should do if you follow order of operations
</span>
Answer:
Step-by-step explanation:
You get 2640 and double it which is 5280 and then do 2640/5280 which is 0.5, that is the amount of miles in 2640 feet. So the answer is 0.5 mph which is C
Answer:PHR
Step-by-step explanation:
PHR means parts per hundred defenition.
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work
EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same
For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y
For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4
Therefore, for the two expressions to be conjugates, we must satisfy the two conditions.
Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the
x²y = -4 ... (I)
Condition 2: Real parts are the same
x² + y = -3 ... (II)
We have a system of equations since both conditions must be satisfied
x²y = -4 ... (I)
x² + y = -3 ... (II)
We can rearrange equation (II) so that we have
y = -3 - x² ... (II)
Substituting into equation (I)
x²y = -4 ... (I)
x²(-3 - x²) = -4
-3x² - x⁴ = -4
x⁴ + 3x² - 4 = 0
(x² + 4)(x² - 1) = 0
(x² + 4)(x-1)(x+1) = 0
Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.
Solve for y:
y = -3 - x² ... (II)
y = -3 - (±1)²
y = -3 - 1
y = -4
So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:
-3 + ix²y
= -3 + i(±1)²(-4)
= -3 - 4i
x² + y + 4i
= (±1)² - 4 + 4i
= 1 - 4 + 4i
= -3 + 4i
They result in conjugates
The answer is not in the choices so ... but the (0,4), (1,1), (2,6)
Hope This Help.
Xd <3
