Hello,
Assume Ax+By+Cz+D=0 the plane 's equation.
p=(0,0,0)==>A*0+B*0+C*0+D=0==>D=0
q=(0,1,0)==>A*0+B*1+C*0+0=0==>B=0
r=(1,2,3)==>A*1+0*2+C*3+0=0==>A=-3C
Let C=1==>A=-3
An equation of the plane is -3x+z=0
C.
This is because the x vale is clearly after the 6 and the y value is right on 5
Answer:
Should be C
Step-by-step explanation:
Only the same power number can be use to add or subtract :)
But why is A, B and C same kinda stuff?
Answer:
25.12
Step-by-step explanation:
Formula: 2πr, r = d/2
Given: π = 3.14, d = 8
Sub: r = 8/2
Simplify: r = 4
Sub: 2(3.14)(4)
Simplify: 6.28(4)
Solve: 25.12
The answer is 0
Explanation
When doing PEMDAS you always move from left to right
4+7=11
-5-6=-11
11-11
= 0