Answer:
Total amount Silas and Raja has at first = $252
Step-by-step explanation:
Let,
Amount Silas had = x
Amount Raja had = y
According to given statement;
x = 3y Eqn 1
x-84 = y+42 Eqn 2
Putting value of x from Eqn 1 in Eqn 2
3y - 84 = y+42
3y-y = 42+84
2y = 126
Dividing both sides by 2

Putting y = 63 in Eqn 1
x = 63(3)
x = 189
Total amount they had = 189 + 63 = $252
Hence,
Total amount Silas and Raja has at first = $252
I ain't Joseph but what's wrong?
X-intercept = -3
y- intercept = -6
Rewrite the fractions to have a common denominator to find the difference:
2/3 = 4/6
Difference = 4/6-5/6 = -1/6
Sequence formula = an = a1 + d(n-1)
A1 is the first term 5/6
And d = -1/6
Sequence = 5/6 -1/6(n-1)
Simplify to get an =(-n +6)/6
Answer:
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