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WITCHER [35]
3 years ago
15

ASAP!! I'll mark you as BRAINLIEST Please help me out here I would really appreciate <3​

Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0

D.

(1) 14 + 2 = 16

(2) 14 + 5 = 19

(3) 14 + x

E.

(1) x + 20

(2) 10 + 20 = 30

(3) 13 + 20 = 33

(4) 35 - 20 = 15

(5) y - 20

(6) x + (x + 20) = 60 | 2x + 20 = 60 | 2x = 40 | x = 20

F.

200 - 148 = 52

52 / 4 = 13 each

G.

500 + 100 = 600

600 / 5 = 120 without the discount

Hope this helps!

cupoosta [38]3 years ago
5 0

Answer:

d) 16, 19, 14 + x

e) x + 20, 30, 33, 15, y - 20, x+x+20=60 and James would be 20.

f) 13

g) 120

Step-by-step explanation:

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An adult female elephant weighs about 8000 pounds. a newborn baby elephant weighs about 200 pounds. write the ratio of the baby
SIZIF [17.4K]
Answer: 1/40 or .025

See the attached image for the explanation.

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.

8 0
2 years ago
Read 2 more answers
If a circle has a radius of 10 how do u find the area
hjlf

Answer:

A = 628.32

Step-by-step explanation:

Area of a circle = 2\pir^{2}

A = 2 x \pi x 10^{2}

A = 628.32

Please mark brainliest, hope this helps!

4 0
3 years ago
What is the ​ IQR ​ for the data set? {61, 70, 59, 55, 69, 59, 62} Drag and drop the correct answer into the box.
True [87]

Answer:

10

Step-by-step explanation:

Interquartile Range Formula:

IQR = Q3 - Q1

Quartiles Quartiles:

Q1 --> 59

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5 0
2 years ago
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4. Solve 5x + 25 = 250 x = ?* Enter the number value only.​
sammy [17]

Answer: x = 5/49 ; 0.102041

Step-by-step explanation:

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3 0
3 years ago
Cos(−θ)=√3/3, sinθ&lt;0
Delicious77 [7]

Answer:

\sin\theta=-\frac{\sqrt{6}}{3}


Step-by-step explanation:

The given trigonometric equation is \cos(-\theta)=\frac{\sqrt{3} }{3}.

We can either use the Pythagorean identity or the right angle triangle  to solve for \sin\theta.

According to the Pythagorean identity,

\cos^2\theta+\sin^2\theta=1


Recall that, the cosine function is an even function, therefore

\cos(-\theta)=\cos(\theta)


\Rightarrow \cos(\theta)=\frac{\sqrt{3} }{3}.

We substitute this value in to the above Pythagorean identity to get;


(\frac{\sqrt{3}}{3})^2+\sin^2\theta=1


\Rightarrow \frac{3}{9}+\sin^2\theta=1


\Rightarrow \sin^2\theta=1-\frac{3}{9}


\Rightarrow \sin^2\theta=\frac{6}{9}


\Rightarrow \sin\theta=\pm \sqrt{\frac{6}{9}}


\Rightarrow \sin\theta=\pm \frac{\sqrt{6}}{3}


But we were given that,

\sin\theta\:, so we choose the negative value.

\Rightarrow \sin\theta=-\frac{\sqrt{6}}{3}


The correct answer is B







7 0
4 years ago
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