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MrRa [10]
3 years ago
14

Isotopes of the same element have a different number of ______​

Chemistry
1 answer:
qaws [65]3 years ago
5 0

Answer:

atomic weight..................

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Determine the number of moles within a sample of 10g of propane(C3H8). Round your answer to 2 decimal places with proper units.
a_sh-v [17]

Given :

10 gram sample of propane( C₂H₈ ).

To Find :

The number of moles of propane in given sample.

Solution :

Molecular mass of propane, M = (2 × 12) + ( 1 × 8 ) gram/mol

M = 32 gram/mol

We know, number of moles is given by :

Number of moles, n = m/M

n = 10/32 mol

n = 0.3125 mol

Therefore, number of moles in given sample is 0.3125 mol.

7 0
3 years ago
A beaker contains 175.32g of salt, NaCl(58.44g/mol). Water is added until the final volume is 2 liters. The solution should be d
cricket20 [7]

Answer:

E. 1.5M

Explanation:

because there is total 175.32 g of NaCl dissolved in 2 liter of water, and 58.44 g = 1 mol

so total miles = 175.32/58.32 = 3 moles

now 3 moles are in 2 liter of water, hence one liter contains 3/2= 1.5

Therefore answer is E. 1.5M

8 0
4 years ago
Consider the following thermochemical equation: C(s) + O2(g) → CO2(g) ΔH = −393 kJ CO(g) + ½O2(g) → CO2(g) ΔH = −294 kJ What is
Oksi-84 [34.3K]

Answer:

B. –99 kJ.

Explanation:

We have the following information:

1. C(s) + O₂(g) → CO₂(g);

ΔH = -393 kJ

2. 2CO(g) + O₂ → 2CO₂(g);

ΔH = -588 kJ

Using Hess's Law, Our target equation has C(s) on the left hand side, so we re-write equation 1:

1. C(s) + O₂(g) → CO₂(g);

ΔH = -393 kJ

So, we reverse equation 2 and divide by 2, we have equation 3:

3. CO₂(g) → CO(g) + ½O₂;

ΔH = +294 kJ

That is, change the sign of ΔH and divide by 2. Then we add equations 1 and 3 and their ΔH values.

This gives:

C(s) +½O₂(g) → CO(g);

ΔH = +294 - 393 kJ

= -99 kJ

The standard enthalpy of formation of carbon monoxide is -99 kJ/mol.

5 0
3 years ago
a sample of gas occupies 2.00 liters under standard conditions. what temperatures would be required for this sample of gas to oc
gogolik [260]

Answer: 1,638

Explanation:

3 0
3 years ago
To which factor can the principles of Nicholas Steno be applied?
Tcecarenko [31]

Answer:

the rock layers of the Grand Canyon

Explanation:

Steno's law are laws that applied to sedimentary rocks. These laws helps in understanding sedimentary sequences.

Sedimentary rocks are derived from the deposition of pre-existing rocks in basins. In order to understand some important relationships between these rock layers, Steno's  law offer a good insight.

Steno's law are often applied when we want to do relative dating of rock layers. Some of the laws are:

  • Law of superposition of strata
  • Law of original horizontality
  • Law of lateral continuity
  • Law of inclusion
  • Law of fossil and fauna succession

These laws helps to interpret sedimentary rock sequences better.

7 0
4 years ago
Read 2 more answers
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