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Alla [95]
3 years ago
8

Ap sublevel has 3 electrons. How should they be arranged

Chemistry
1 answer:
inna [77]3 years ago
8 0

Answer:

If a sublevel p has 3 electrons, all electrons are in the first p orbital .

Explanation:

According to the rules for establishing the energy level of an element, the sublevel "p" has a capacity for 6 electrons, so a sublevel p with 3 electrons will accept all of those electrons.

An example is nitrogen, with Z = 7, whose electronic level can be written

1s²2s² 2p³

- Two electrons on level 1 sublevel s

- Five electrons on level 2, of which two are in sublevel s and three in sublevel p.

The other options are incorrect:

<em>   A and C. It is not possible, because p accepts up to 6 electrons.</em>

<em>   D. All sublevels "s" accept up to two electrons, with the exception of hydrogen (z = 1) which has only one electron in the first sublevel s 1s¹.</em>

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Suppose 9 glucose molecules enter glycolysis. Calculate the number of inorganic phosphate molecules required as well as the numb
Aleksandr-060686 [28]

Answer:

18 inorganic phosphates and 18 pyruvates.

Explanation:

Glycolysis is the pathway involved in the metabolism of sugar. It is enzyme catalyze and converts glucose into pyruvate and a Hydrogen ion.

The free energy released are the used to form high-energy molecules such as ATP and NADH.

The net ATP production of Glycolysis involving a molecule of Glucose are 2 ATPs ,2 NADH and 2 pyruvates.

If 9 molecules of glucose enter glycolysis,then it has to be multiplied by 9 to give 18 pyruvates and 18 net ATPs

6 0
4 years ago
How many carbon atoms are there in a diamond (pure carbon) with a mass of 55 mg ?
kari74 [83]
1 mol of Carbon = 12 grams.
x mol of Carbon = 55 grams

12*x = 1 * 55
x = 55/12
x = 4.583333 mols of carbon

1 mol of anything is 6.02 * 10^23 atoms
4.58333333 mol = x

1/4.5833333 = 6.02 * 10^23/x
x = 4.58333* 6.02*10^23
x = 2.7591 * 10^23 Carbon atoms
3 0
3 years ago
(vii). Give two uses of chlorine gas.​
Strike441 [17]

Answer: A yellowy-green dense gas with a choking smell. Chlorine kills bacteria – it is a disinfectant. It is used to treat drinking water and swimming pool water. It is also used to make hundreds of consumer products from paper to paints, and from textiles to insecticides.

Explanation: hope this helps u! HAppy Holidays!  

7 0
3 years ago
How did Henry Moseley revise Mendeleev's periodic table? (Please answer A.S.A.P.)
CaHeK987 [17]
<span>If you give it a good search, the most used answer would probably be as follows,

</span><span>In 1914 Henry Moseley found a relationship between an element's X-ray wavelength and its atomic number (Z), and therefore rearranged the table by nuclear charge / atomic number rather than atomic weight. Before this discovery, atomic numbers were just sequential numbers based on an element's atomic weight. Moseley's discovery showed that atomic numbers had an experimentally measurable basis.
</span>
Hope this helps!
5 0
3 years ago
Read 2 more answers
Naturally occurring element X exists in three isotopic forms: X-28 (27.979 amu, 92.21% abundance), X-29 (28.976 amu 4.70% abunda
bezimeni [28]

<u>Answer:</u> The average atomic mass of X is 28.09 amu

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i .....(1)

  • <u>For isotope 1:</u>

Mass of isotope 1 = 27.979 amu

Percentage abundance of isotope 1 = 92.21 %

Fractional abundance of isotope 1 = 0.9212

  • <u>For isotope 2:</u>

Mass of isotope 2 = 28.976 amu

Percentage abundance of isotope 2 = 4.70 %

Fractional abundance of isotope 2 = 0.0470

  • <u>For isotope 3:</u>

Mass of isotope 3 = 29.974 amu

Percentage abundance of isotope 3 = 3.09 %

Fractional abundance of isotope 3 = 0.0309

Putting values in equation 1, we get:

\text{Average atomic mass of X}=[(27.979\times 0.9212)+(28.976\times 0.0470)+(29.974\times 0.0309)]

\text{Average atomic mass of X}=28.09amu

Hence, the average atomic mass of X is 28.09 amu

4 0
3 years ago
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