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Softa [21]
4 years ago
6

Which energy changes in the enthalpy of solution are endothermic, and which are exothermic?

Chemistry
1 answer:
snow_tiger [21]4 years ago
8 0
When energy is needed in order for the reaction to happen, then that reaction is known as endotermic. When the reaction has as a result energy then it is exotermic. An example of an endotermic reaction would be photosynthesis, for an exotermic: combustion.
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When an acid reacts with a base, salt and water is formed! Why??​
vladimir1956 [14]

Answer:

When n acid reacts with a base , salt and water is formed because when acid reacts with base, it loses its acidic property and base loses its basic property to form a neutral substance like salt and water..

5 0
4 years ago
Read 2 more answers
Help me with this now please due in 20 mins
user100 [1]
Ca(oh) 2 is calcium hydroxide
So
Calcium in one box
Hydroxide in the other.
Hope this helps!
8 0
3 years ago
Give the electron configuration of vanadium (V), atomic number 23
saveliy_v [14]

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d³ or [Ar] 4s²3d³

<h3>Further explanation</h3>

Given

Vanadium, atomic number 23

Required

The electron configuration

Solution

In an atom, there are levels of energy in the shell and subshell  

This energy level is expressed in the form of electron configurations.  

Charging electrons in the subshell uses the following sequence:  

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  </em>

The electron configuration is based on the atomic number which indicates the number of electrons of the atom

Vanadium has the atomic number 23, so the number of electrons = 23

Electron configuration:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d³

or we can write it using the noble gas notation

[Ar] 4s²3d³

4 0
3 years ago
Write the chemical equations involved in this experiment and how that the rate of disappearance of [S2O8^2-] is proportional to
Ne4ueva [31]

S₂O₈²⁻

(aq) + 2I⁻

(aq) → I₂(aq) + 2SO₄

²⁻(aq)

2S₂O₃²⁻

(aq) + I₂(aq) → S₄O₆²⁻

(aq) + 2I⁻

(aq)

<u>Explanation:</u>

S₂O₈²⁻

(aq) + 2I⁻

(aq) → I₂(aq) + 2SO₄

²⁻(aq)

To measure the rate of this reaction we must measure the rate of concentration change of one of  the reactants or products. To do this, we will include (to the reacting S₂O₈

²⁻  and I⁻

i) a small amount of sodium thiosulfate, Na₂S₂O₃,

ii) some starch indicator.

The added Na₂S₂O₃ does not interfere with the rate of above reaction, but it does consume the I₂  as soon as it is formed.

2S₂O₃²⁻

(aq) + I₂(aq) → S₄O₆²⁻

(aq) + 2I⁻

(aq)

This reaction is much faster than the previous, so the conversion of I2 back to I⁻  is  essentially instantaneous.

rate = \frac{dI2}{dt} = \frac{1/2 [S2O3^2^-]}{t}

5 0
3 years ago
1. A student is examining a cell through a microscope. She notes the
Hoochie [10]
C

Animal cells do not have cell walls or chloroplasts!
3 0
3 years ago
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