Answer:
The content that follows is the substance of lecture 14. In this lecture we cover the use of balanced chemical equations to make mole and mass predictions in reaction. Reaction stoichiometry is a fancy way of describing mole relations in a reaction. When we read a balanced equation we relate every compound in the reaction to the others by means of the mole coefficients in the reaction. For example: HCl + NaOH → NaCl + H2O This equation is all 1:1 relationships, 1 mole of NaCl is made for every 1 mole of HCl or NaOH etc. In a previous lecture I introduced the following analogy: What can we do with a balanced equation? A chemical reaction equation is essentially a table of conversion factors that we can use to predict amounts of products that can be made, reactants needed to make a specific amount of product or exact amounts of reactants needed to completely consume another reactant (eg. acid and base neutralization). While the use of the stoichiometry (fancy words for mole relationships in a reaction equation) may seem difficult, it really isn't. Let's use an example that you all can understand first: 1 slice bologna + 2 slices of bread → 1 Sandwich If I asked you how many sandwiches you could make with 12 slices of bread, you would immediately say 6, right? How did you know this? Well, obviously based on the equation, you make 1 sandwich for every 2 slices of bread you have.12 slices bread x 1 sandwich/2 slices bread = 6 sandwiches If I asked you how many slices of bologna and bread you need to create 10 sandwiches, you would immediately say 10 slices of bologna and 20 slices of bread, right? Again the relationship given in the equation tells you how much is needed. 10 sandwiches x 1 slice bologna/1 sandwich = 10 slices bologna and 10 sandwiches x 2 slices bread/1 sandwich = 20 slices bread Finally if I asked you how many sandwiches you could make with 5 slices of bologna and 8 slices of bread? Which of the two sandwich makings would run out first and how much of the excess makings would be left over? Well, the answers are 4 sandwiches could be made and 1 slice of bologna is left over. 5 slices of bologna x 1 sandwich/1 slice bologna = 5 sandwiches 8 slices bread x 1 sandwich/2 slices bread = 4 sandwiches 8 slices bread x 1 slice bologna/2 slices bread = 4 slices of bologna used 5 slices bologna - 4 slices used = 1 slice left over
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Explanation:
Answer:
(b) When 20.0 g of nitrogen and 32.0 g of oxygen are combined and allowed to react in two separate experiments, both times the product isolated from reaction contains 14.0 g of nitrogen and 32.0 g of oxygen.
Explanation:
The law of definite proportion states that a gen chemical compound always contains its constituent elements in a fixed ratio by mass, independent on the method of preparation.
The molar mass of Nitrogen and Oxygen would always remain the same, allowing for exact reactant masses (or mole ratio) irrespective of the given amount of sample.
Answer:
The answer to your question is V2 = 5.09 l
Explanation:
Data
Volume 1 = V1 = 5.0 L
Temperature 1 = T1 = 5°C
Volume 2 = V2 = ?
Temperature 2 = T2 = 10°C
Formula (Charles law)
V1/T1 = V2/T2
-Solve for V2
V2 = V1T2 / T1
-Convert temperature to °K
T1 = 5 + 273 = 278°K
T2 = 10 + 273 = 283°K
-Substitution
V2 = (5)(283) / (278)
-Simplification
V2 = 1415 / 278
-Result
V2 = 5.09 l
Answer: 32.94 g
Explanation: It's stoichiometry problem so balanced equation is required. The balanced equation is given below:
From the balanced equation, krypton and chlorine react in 1:2 mol ratio. We will calculate the moles of each reactant gas using ideal gas law equation(PV = nRT) and then using mol ratio the limiting reactant is figured out that helps to calculate the amount of the product formed.
for Krypton, P = 0.500 atm and for chlorine, P = 1.50 atm
V = 15.0 L
T = 350.8 + 273 = 623.8 K
For krypton, 
n = 0.146 moles
for chlorine, 
n = 0.439
From the mole ratio, 1 mol of krypton reacts with 2 moles of chlorine. So 0.146 moles of krypton will react with 2 x 0.146 = 0.292 moles of chlorine.
Since 0.439 moles of chlorine are available, it is present in excess and hence the limiting reactant is krypton.
So, the amount of product formed is calculated from moles of krypton.
Molar mass of krypton tetrachloride is 225.61 gram per mol.
There is 1:1 mol ratio between krypton and krypton tetrachloride.
= 32.94 g of 
So, 32.94 g of the product will form.
