3 years ago

Explain the structure of XeO3

1 answer:

4 0

The central Xe atom in XeO3 has three bonding domains and one lone pair of electrons. Hence, the electron geometry is tetrahedral and molecular geometry is pyramidal.

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What is the product of this chemical reaction?<br>"Copper(II) Sulfate reacts with Potassium Iodide"

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4 years ago

Determine the volume of distilled water that should be added to 20.0 mL of 12.0 M HCl(aq) in order to prepare a 0.500 M HCl(aq)

BARSIC [14]

Answer:

$V_{H_2O}=460 mL$

Explanation:

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In this case, in a dilution process, water is added to a solute in order to decrease its concentration but increase the volume of the solution. It means that if we have 20.0 mL of a 12.0-M solution of HCl and we want a 0.500-M solution, we need to apply the following formula considering that the moles remain unchanged:

$M_1V_1=M_2V_2$

Thus, solving for the final volume is:

$V_2=\frac{M_1V_1}{M_2}$

So plugging in the values we obtain:

$V_2=\frac{12.0M*20.0mL}{0.500M}\\\\V_2=480 mL$

Now, since the initial volume of acid was 20.0 mL and the final volume is 480 mL, the added volume of distilled water is:

$V_{H_2O}=480-20=460 mL$

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3 years ago

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4 years ago

How many milliliters of 50 by mass hno3 solution, with a density of 2.00 grams per milliliter are required to make 500 ml

den301095 [7]

Answer:

V = 331.13 mL of 50 by mass NO3 solution

Explanation:

∴ δ sln = 2.00 g/mL

∴ %m HNO3 = 50% = ( mass HNO3 / mass sln ) × 100

∴ V required sln = 500 mL

∴ δ HNO3 = 1.51 g/mL.......from literature

⇒ V sln = mass sln / δ sln = 500 mL

⇒ mass sln = (500 mL )×( 2 g/mL ) = 1000 g sln

⇒ mass HNO3 = ( 0.5 )×(1000 g) = 500 g HNO3

⇒ V HNO3 = ( 500 g HNO3 )×(ml HNO3/1.51 g ) = 331.13 mL

5 0

3 years ago

Explain the structure of XeO3​

Explain the structure of XeO3