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nikklg [1K]
3 years ago
13

I'm stuck- lol. I'll give brainliest to the first correct answer! :D

Mathematics
1 answer:
polet [3.4K]3 years ago
8 0

Answer:

Its 4:)

Step-by-step explanation:

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\text{Hey there!}

\text{Distribute the value of 7 in each of your terms}

\text{(2x}^3+\text{3y}^2)(7)

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\text{3y}^2\times7=\text{21y}^2

\text{We cannot combine like terms because they AREN'T any in this equation}

\boxed{\boxed{\bf{Answer:14x^3+21y^2}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

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