1 and one - twelfth
because 12gies 3 times in 37
A = P*e^(rt)
Here,
A = $4000*e^(0.051*2) = $4000*e^1.02 = $4000(2.773) = $11092.78
Note: This seems very high to me.
Answer:
Option C
Step-by-step explanation:
We are given a coefficient matrix along and not the solution matrix
Since solution matrix is not given we cannot check for infinity solutions.
But we can check whether coefficient matrix is 0 or not
If coefficient matrix is zero, the system is inconsistent and hence no solution.
Option A)
|A|=
since II row is a multiple of I row
Hence no solution or infinite
OPtion B
|B|=
Hence no solution or infinite
Option C
Hence there will be a unique solution
Option D
=0
(since I row is -5 times III row)
Hence there will be no or infinite solution
Option C is the correct answer