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Dmitry [639]
2 years ago
5

Tom made a vegetable pizza and a pepperoni pizza. he cut the vegetable pizza into 5 slices and the pepperoni pizza into 10 equal

slices Tom's friends ate 2 slices of vegetable pizza and 4 slices of pepperoni pizza. Construct Arguments Tom says his friends ate the same amount of vegetable pizza as pepperoni pizza how could that be true?**​
Mathematics
2 answers:
Anon25 [30]2 years ago
5 0
I may not be the best at this but I believe that Tom’s friends ate the same amount of pepperoni pizza to vegetable pizza because He cut the pizza into 5 slices as to the pepperoni into 10 slices is. The fraction of Vegetable to Pepperoni is 1/2 so 2 vegetable slices is the same amount as 4 slices because the pepperoni pizza is in smaller sizes compared to the Vegetable pizza.
sveticcg [70]2 years ago
5 0

Answer:

That could be true because they are equivalent.

Step-by-step explanation:

They are equivalent because one slice of the vegtable pizza is equal to 2 little slices 1/5=2/10 , 2/5 = 4/10 , 3/5 = 6/10 , 4/5 = 8/10 5/5 = 10/10 . So you basicly cut each fifth into half

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gogolik [260]

Answer:

1/3 in decimal format is .333333333333... so none of these are correct

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WHICH ONE DOESN'T BELONG? Which figure does not belong with the other three? Explain your reasoning.
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The sphere. All the others are prisms.
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11,22,22,13,24,22 find the hunderds too
earnstyle [38]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F
Wewaii [24]

Answer:

1. P(x) ÷ Q(x)---> \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x)---> \frac{2(6x - 1)}{(3x - 1)(-3x + 2)}

3.  P(x) - Q(x)---> \frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) --> \frac{12}{(3x - 1)(-3x + 2)}

Step-by-step explanation:

Given that:

1. P(x) = \frac{2}{3x - 1}

Q(x) = \frac{6}{-3x + 2}

Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

\frac{2}{3x - 1}*\frac{-3x + 2}{6}

\frac{2(-3x + 2)}{6(3x - 1)}

= \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}

\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}

\frac{12x - 2}{(3x - 1)(-3x + 2)}

= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}

3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}

\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}

\frac{-24x + 10}{(3x - 1)(-3x + 2)}

= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}

P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}

4 0
3 years ago
The reflection pool is 1 meter deep, 10 meters wide, and 20.5 meters long. What is the volume of the pool
gtnhenbr [62]
Volume = length x width x height
Volume = 1 x 10 x 20.5
Volume = 205 m^3
3 0
3 years ago
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