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sveticcg [70]
4 years ago
13

A horse pulls a wagon that weighs 10 times more than the horse. The horse pulls with a force of 500N to move the wagon forward.

How much force does the wagon exert on the horse? *
a. More than 500N
b. It depends on the size of the horse
c. Less than 500N
d. 0N because a wagon cannot exert a force
e. 0N because the wagon is moving
f. 500N
Physics
1 answer:
____ [38]4 years ago
5 0

Answer:

f. 500N

Explanation:

The force exerted by the wagon on the horse is 500N directed in the opposite path .

This is premised on the Newton's third law of motion which states that "action and reaction forces are equal and opposite in direction".

So, as the action force of 500N is used by the horse to drag the wagon, the wagon also exerts an oppositely directed force of 500N on the horse.

This way, the acceleration can continue.

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Absolute pressure in tank is P1 = 260 kPa and local ambient absolute pressure is P2 =100 kPa. If liquid density in pipe is 13600
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Answer:

1.176m

Explanation:

Local ambient pressure(P1) = 100 kPa

Absolute pressure(P2)=260kPa

Net pressure=absolute pressure-local ambient absolute pressure

Net pressure=P1(absolute pressure)-P2(local ambient absolute pressure)

Net pressure=260-100=160kPa

Pressure= ρgh

160kPa=13600*10*h

h=\frac{160000}{136000}

h=1.176m

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Answer:

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Explanation:

Two identical sticky masses m are moving in the xy-plane, with their momenta at an angle of φ with one another. They are each moving at the same speed v when they collide at the origin of the coordinates and stick together. After the collision, the masses move at an angle −θ2 with respect to the +x axis at speed v2 .1. What was the angle φ?

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In a system of colliding bodies,we know that the total momentum before collision will equal to the total momentum after collision.

Take note that momentum is the product of mass and velocity

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mass, m

u=initial velocity of the identical masses

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Note that the collision is inelastic , since they both moved with the same velocity

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2mucosφ=2mv2cos−θ2

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