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Igoryamba
2 years ago
9

A mover pushes a 45 kg crate across a level floor with a force of 300 N, but the crate accelerates at a rate of only 4.44 m/s2 b

ecause a friction force opposes the crate's motion. What is the magnitude of this force of friction? 300 N Force of Friction O A. 50 N N OB. 25 N C. 15 N 0 D. 100 N​
Physics
1 answer:
Sidana [21]2 years ago
3 0

By Newton's second law, the net force on the crate is

∑ <em>F</em> = 300 N - <em>f</em> = (45 kg) (4.44 m/s²)

where <em>f</em> is the magnitude of friction. Solve for <em>f</em> :

300 N - <em>f</em> = (45 kg) (4.44 m/s²)

<em>f</em> = 300 N - (45 kg) (4.44 m/s²)

<em>f</em> = 100.2 N ≈ 100 N (D)

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