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Marta_Voda [28]
3 years ago
8

Find the slope of the line that passes through (3,6) and (1,3)​

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0
(6-3)/(3-1) = 3/2

3/2 is the slope
Thepotemich [5.8K]3 years ago
5 0

Answer:

-1

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Find lim x→3 sqrt 2x+3-sqrt 3x/ x^2-3x. you must show your work or explain your work in words plsss I need help
sineoko [7]

I'm assuming the limit is supposed to be

\displaystyle\lim_{x\to3}\frac{\sqrt{2x+3}-\sqrt{3x}}{x^2-3x}

Multiply the numerator by its conjugate, and do the same with the denominator:

\left(\sqrt{2x+3}-\sqrt{3x}\right)\left(\sqrt{2x+3}+\sqrt{3x}\right)=\left(\sqrt{2x+3}\right)^2-\left(\sqrt{3x}\right)^2=-(x-3)

so that in the limit, we have

\displaystyle\lim_{x\to3}\frac{-(x-3)}{(x^2-3x)\left(\sqrt{2x+3}+\sqrt{3x}\right)}

Factorize the first term in the denominator as

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The x-3 terms cancel, leaving you with

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3 years ago
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