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mixer [17]
3 years ago
9

Lisa, an experience shipping clerk, can fill a certain order in 10 hours. Bill, a new clerk, needs 13 hours to do the same job.

Working together, how long will it take them to fill the order
Mathematics
1 answer:
Lelu [443]3 years ago
7 0
I think 11 hours and 30 minutes
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Yvette is considering taking out a loan with a principal of $16,200 from one of two banks. Bank F charges an interest rate of 5.
umka21 [38]
Hi there
First find the monthly payment of each offer to see which monthly payment is lower
The formula of the present value of annuity ordinary is
Pv=pmt [(1-(1+r/k)^(-kn))÷(r/k)]
Pv present value
PMT monthly payment
R interest rate
K compounded monthly 12
N time
Solve the formula for PMT
PMT=pv÷[(1-(1+r/k)^(-kn))÷(r/k)]

Bank F
PMT=16,200÷((1−(1+0.057÷12)^(
−12×8))÷(0.057÷12))
=210.53

Bank G
PMT=16,200÷((1−(1+0.062÷12)^(
−12×7))÷(0.062÷12))
=238.21

From the above the monthly payment of bank f is lower than the bank g
And since the lifetime of bank g is lower than bank f the answer is
b. Yvette should choose Bank F’s loan if she cares more about lower monthly payments, and she should choose Bank G’s loan if she cares more about the lowest lifetime cost.

Good luck!


6 0
3 years ago
To convert a distance of 12000 feet to miles which ratio could you multiply by?
Luba_88 [7]

Answer:

2.28 miles

Step-by-step explanation:

1 foot = 0.00019miles

12000 feet = x miles

Cross multiply

x = 12000 x 0.00019

x = 2.28 miles

5 0
3 years ago
If two cards are randomly drawn from a standard 52-card deck, what is the probability that both cards are hearts?
Anettt [7]

Answer:

26

Step-by-step explanation:

You have to divide the two numbers, which are 2 and 52

5 0
3 years ago
A store selling newspapers orders only n = 4 of a certain newspaper because the manager does not get many calls for that publica
umka2103 [35]

Answer:

a) The expected value is 2.680642

b) The minimun number of newspapers the manager should order is 6.

Step-by-step explanation:

a) Lets call X the demanded amount of newspapers demanded, and Y the amount of newspapers sold. Note that 4 newspapers are sold when at least four newspaper are demanded, but it can be <em>more</em> than that.

X is a random variable of Poisson distribution with mean \mu = 3 , and Y is a random variable with range {0, 1, 2, 3, 4}, with the following values

  • PY(k) = PX(k) = ε^(-3)*(3^k)/k! for k in {0,1,2,3}
  • PY(4) = 1 -PX(0) - PX(1) - PX(2) - PX (3)

we obtain:

PY(0) = ε^(-3) = 0.04978..

PY(1) = ε^(-3)*3^1/1! = 3*ε^(-3) = 0.14936

PY(2) = ε^(-3)*3^2/2! = 4.5*ε^(-3) = 0.22404

PY(3) = ε^(-3)*3^3/3! = 4.5*ε^(-3) = 0.22404

PY(4) = 1- (ε^(-3)*(1+3+4.5+4.5)) = 0.352768

E(Y) = 0*PY(0)+1*PY(1)+2*PY(2)+3*PY(3)+4*PY(4) =  0.14936 + 2*0.22404 + 3*0.22404+4*0.352768 = 2.680642

The store is <em>expected</em> to sell 2.680642 newspapers

b) The minimun number can be obtained by applying the cummulative distribution function of X until it reaches a value higher than 0.95. If we order that many newspapers, the probability to have a number of requests not higher than that value is more 0.95, therefore the probability to have more than that amount will be less than 0.05

we know that FX(3) = PX(0)+PX(1)+PX(2)+PX(3) = 0.04978+0.14936+0.22404+0.22404 = 0.647231

FX(4) = FX(3) + PX(4) = 0.647231+ε^(-3)*3^4/4! = 0.815262

FX(5) = 0.815262+ε^(-3)*3^5/5! = 0.91608

FX(6) = 0.91608+ε^(-3)*3^6/6! = 0.966489

So, if we ask for 6 newspapers, the probability of receiving at least 6 calls is 0.966489, and the probability to receive more calls than available newspapers will be less than 0.05.

I hope this helped you!

8 0
3 years ago
HEEEEEELP MEEE PLEASEEEE ;(
BaLLatris [955]

If There is a math equation you can use math-way.

Also it would help if you can take a better picture.

Once you take a better picture I promise i will try my best to answer the question.

7 0
3 years ago
Read 2 more answers
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