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Ierofanga [76]
3 years ago
5

A waterfall is an example of what energy conversion?

Physics
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer:

most common energy transformations is the transformation between potential energy and kinetic energy. In waterfalls such as Niagara Falls, potential energy is transformed to kinetic energy. The water at the top of the falls has gravitational potential energy. As the water plunges, its velocity increases.

Explanation:

Hope this helps you

( I got this from transformation and conservation article)

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A charge q is at the point x = 5.0 m , y = 0. Write expressions for the unit vectors you would use in Coulomb's law if you were
Flauer [41]

Answer:

A) \^r = \^y

B) \^r = -\^x

C) \^r = -0.14\^x + 0.99\^y

Explanation:

Coulomb's Law is

\vec{F}_{ab} = K\frac{q_1q_2}{r^2}\^r

where r is the distance between the two point charges.

The question clearly asks the unit vector expressions of the force that q exerts on the other charge. So, we do not need to find the force, but only the distance vector, r, between charges, and then we can derive the unit vector pointing only the direction of the force.

A) \vec{r} = \vec{r}_b - \vec{r}_a = (5\^x + \^y) - (5\^x + 0) = \^y\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{\^y}{1} = \^y

B) \vec{r} = \vec{r}_b - \vec{r}_a = (0 + 0) - (5\^x + 0) = -5\^x\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{-5\^x}{5} = -\^x

C) \vec{r} = \vec{r}_b - \vec{r}_a = (4.5\^x + 3.5\^y) - (5\^x + 0) = -0.5\^x + 3.5\^y\\\^r = \frac{\vec{r}}{|\vec{r}|} = \frac{-0.5\^x + 3.5\^y}{\sqrt{(0.5)^2+(3.5)^2}} = \frac{-0.5\^x + 3.5\^y}{3.53} = -0.14\^x + 0.99\^y

7 0
3 years ago
Read 2 more answers
The aorta is the main artery from the heart. a typical aorta has an inside diameter of 1.8 cm and carries blood at speeds of up
defon

Answer:

Explanation:

Volume per unit time flowing   will be conserved

a₁v₁  = a₂ v₂

π r₁² x v₁ = π r₂² x v₂

(0.9 x 10⁻²)² x .35 = ( .45 x 10⁻² )² x v₂

v₂ = 1.4 m / s

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3 years ago
At time t=0 , in your frame of reference Z, you measure the back of the spaceship to be at x=0 and the front of the ship to be a
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An equation relating the length that you measure l to the ship's proper length l0  is  

l =l0/y. This is further explained below.

<h3>What is an equation relating the length that you measure l to the ship's proper length l0?</h3>

Generally, Any object's length in a moving frame will look shortened or contracted when seen in that direction. The Lorentz transformation may be used to determine the amount of contraction.

In conclusion, To use the Lorentz Lorentz transformation, the length Lo-x2 - may be determined if it is measured in the moving reference frame. Hence the Resultant l = l0/y.

Read more about Lorentz transformation

brainly.com/question/16284701

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3 years ago
A penny rides on top of a piston as it undergoes vertical simple harmonic motion with an amplitude of 4.0cm. If the frequency is
nadezda [96]

Answer:

in the downward movement of the movement when the constant is lost

Explanation:

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       a = d²x / dt²

the piston position is

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the maximum acceleration is

     a = - A w²

When the piston raises the acceleration of gravity and that of the piston go in the same direction, when the piston descends they relate it is contrary to gravity, therefore when the frequency increases, the point where the acceleration of the piston is greater than gravity arrives and the coin loses contact.

The point where you lose contact is

      a = g

      g = A w²

In short, in the downward movement of the movement when the constant is lost

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If you want to conduct an electrical current, which situation would produce a solution capable of this? A) Dissolving water in o
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D dissolving solid NaF in water

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