Work is Force X Distance. The force is equal to mass X acceleration (F=MA). In this case the acceleration is gravity, which is 9.81 m/s^2. So you multiply 500 by 9.81 to get 4905 Newtons (N). This is the amount of force required to lift the safe. Multiply this force by the distance, which in this case is 90 meters. This gives you 441450 Newton Meters (N*m) of work. 1 N*m is equivalent to 1 Joule (J), so the answer can be written as 441450 Joules (J).
Answer:
1) The final displacement of cyclist is 20.8 km.
2) The average velocity of cyclist is 18.35 m/h
Explanation:
The path traced by the cyclist is as shown in the attached figure
from the attached figure we can see
1) Initial distance covered = 8.0 km east therefore OA = 8.0 km
2) When the cyclist turns and travels 3.2 km west thus AB = 3.2 km
3) From B the cyclist turns and travels 16 km east thus BC = 16.0 km
As we can see that the total displacement is OC = OA- AB + BC = 8.0-3.2+16 = 20.8 km
Thus the final displacement is 20.8 km.
Part b)
By definition of average velocity we have
Their skin is thin and moist so they can breath underwater
<span>Energy of Photon emitted by heated lithium atom E = 2.961 Ă— 10â’19 J
We need energy for only one mole of photons n = 1
Total photons in one mole = 6.022x10^23 photons / mole
Total Energy = n x h x E => 1 x 6.022x10^23 x 2.961 Ă— 10^â’19
Total Energy = 1.783x10^5 J</span>