Answer:
14x^-10x+12+2=-140x+14
Step-by-step explanation:
Very simple. Just add/multiply the like terms, (14x^-10x & 12+2), and then you'll get the answer, but since 140x and 14 are not like terms, the answer stays as 140x+14.
Answer:
Account A: Decreasing at 8 % per year
Account B: Decreasing at 10.00 % per year
Account B shows the greater percentage change
Step-by-step explanation:
Part A: Percent change from exponential formula
f(x) = 9628(0.92)ˣ
The general formula for an exponential function is
y = ab^x, where
b = the base of the exponential function.
if b < 1, we have an exponential decay function.
ƒ(x) decreases as x increases.
Account A is decreasing each year.
We can rewrite the formula for an exponential decay function as:
y = a(1 – b)ˣ, where
1 – b = the decay factor
b = the percent change in decimal form
If we compare the two formulas, we find
0.92 = 1 - b
b = 1 - 0.92 = 0.08 = 8 %
The account is decreasing at an annual rate of 8 %.The account is decreasing at an annual rate of 10.00 %.
Account B recorded a greater percentage change in the amount of money over the previous year.
What are the solutions of this system of equations? Select all that apply. y = x2 − x − 3 y = −3x + 5
Answer: I think there is a mistake for the first one because I did the math and I got 200 added but then there are more answers to this one, I added all the others by 200 and got the next number but then when I got to 6,300 I can't get the 6,700. I get something else, I add 6,000 with 200, and then I get 6,200 instead of getting 6,300. Then I added that 6,200 and 200 and got 6,400. I am confused with the second one, can you please help me understand that one. The third one is also confusing, The one is 12 nuggets eaten per minute. The fifth I am not sure if that is a solvable question, The sixth one I am not sure but I think that it is 0.066667. The seventh one doesn't even make any sense to me.
Explanation: I am sorry this was so long, I was trying to make sense of these questions. Also if this is ALL wrong sorry for even trying.
