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3 years ago

8

How death rate helps in changing population

1 answer:

lapo4ka [179]3 years ago

6 0

Both the birth and death rate are expressed per 1000 of the population.

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What's going to happen in 3 weeks ?

Nana76 [90]

<u><em>Answer:</em></u>

<u><em>god knows.</em></u>

Explanation:

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3 years ago

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A ball is accelerating down a hill. Which statement is true?

Andrew [12]

Answer:

The potential energy increases and the kinetic energy decreases

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3 years ago

Electric resistance ____________ with a(n) ____________in the length of a wire and as a result current flow ___________.

maria [59]

The answer is D. Electric resistance increases with an increase in the length of a wire and as a result current flow decreases. There is a direct relationship between the length of the wire and the resistance. The longer the wire, the more resistance there will be. Additionally, from Ohm's Law, current is inversely proportional to resistance. This means as the current increases, resistance decreases or vice versa.

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3 years ago

An irregular object of mass 3 kg rotates about an axis, about which it has a radius of gyration of 0.2 m, with an angular accele

Citrus2011 [14]

Answer:

The magnitude of the applied torque is $6.0\times10^{-2}\ N-m$

(e) is correct option.

Explanation:

Given that,

Mass of object = 3 kg

Radius of gyration = 0.2 m

Angular acceleration = 0.5 rad/s²

We need to calculate the applied torque

Using formula of torque

$\tau=I\times\alpha$

Here, I = mk²

$\tau=mk^2\times\alpha$

Put the value into the formula

$\tau=3\times(0.2)^2\times0.5$

$\tau=0.06\ N-m$

$\tau=6.0\times10^{-2}\ N-m$

Hence, The magnitude of the applied torque is $6.0\times10^{-2}\ N-m$

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4 years ago

A 2000-kg railway freight car coasts at 4.4 m/s underneath a grain terminal, which dumps grain directly down into the freight ca

ruslelena [56]

Answer:

933. 3kg

Explanation:

We are given that

Mass,m=2000 kg

Initial speed,u=4.4 m/s

We have to find the maximum mass of grain if the speed of loaded freight car must not go below 3.0 m/s.

Final speed,v=3 m/s

By conservation of momentum

Initial momentum=Final momentum

$mu=m'v$

Substitute the values

$2000\times 4.4=m'(3)$

$m'=\frac{2000\times 4.4}{3}$

$m'=2.93\times 10^3 kg$

Mass of freight loaded car=2933.3 kg

Mass of grains=2933.3-2000=933.3 kg

Hence, the maximum mass of grains that it can accept=933.3 kg

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3 years ago