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SIZIF [17.4K]
3 years ago
15

A motorist travels 406 km, West during a 7.0 hr period. What was the average velocity in (a) km/hr and (b) m/sec?

Physics
1 answer:
AVprozaik [17]3 years ago
6 0
Average velocity = (displacement) / (travel time)

Without more details, I just have to assume that the 406 km
is the displacement ... that is, the straight-line distance between
the start point and the end point.  If there were any turns, loops,
or backtracks during the trip, then this question couldn't be answered,
because we don't know the displacement. 

a). Average velocity = (406 km) / (7.0 hours) = 58 km/hr West.

According to the requirements stated in the question, I still
have to convert this answer to a different unit in order to 
rightfully claim the full 5-points bounty.

b). (58 km/hour) x (1,000 m/km) x (1 hour / 3600 sec) =  16-1/9 m/sec .
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Consider a satellite in a circular orbit around the earth. Why is it important to give a satellite a horizontal speed when placi
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In this case, the horizontal velocity of the rocket starts from the acceleration, so if its velocity drops to zero,

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3 years ago
Which two particles are present in the nucleus of an atom? Electrons and neutrons Electrons and molecules 1 TH O Protons and neu
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2 years ago
In the ground state of hydrogen, according to the Bohr model, an electron orbits 5.3 x 10-11 m from the nucleus. It undergoes a
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Answer:

Explanation:

Given

radius of electron(r)=5.3\times 10^{-11} m

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a_c=\frac{v^2}{r}

v=\sqrt{r\times a_c}

v=\sqrt{5.3\times 10^{-11}\times 9\times 10^{22}}

v=\sqrt{47.7\times 10^11}

v=21.84\times 10^5 m/s

(b)For n=10

r=100\times 5.3\times 10^{-11} m\approx 5.3\times 10^{-9} m

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a_c=9\times 10^{26} m/s^2

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v=21.84\times 10^8 m/s

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