The energy achieved I think
Answer:
The maximum emf induced in the ring
= (2.882 × 10⁻⁷) V
Explanation:
According to the law of electromagnetic induction, the emf induced in the ring is given by
E = N BA w sin wt
The maximum emf induced is
E = N BA w
B = 30.5 μT = (30.5 × 10⁻⁶) T
A = (πD²/4)
D = 1.75 cm = 0.0175 m
A = (π×0.0175²/4) = 0.000240625 m²
Nw = 2π × 6.25 = 39.29 rad/s
E = 30.5 × 10⁻⁶ × 0.000240625 × 39.29
E = (2.882 × 10⁻⁷) V
Hope this Helps!!!
Answer:
(B) 13.9 m
(C) 1.06 s
Explanation:
Given:
v₀ = 5.2 m/s
y₀ = 12.5 m
(A) The acceleration in free fall is -9.8 m/s².
(B) At maximum height, v = 0 m/s.
v² = v₀² + 2aΔy
(0 m/s)² = (5.2 m/s)² + 2 (-9.8 m/s²) (y − 12.5 m)
y = 13.9 m
(C) When the shell returns to a height of 12.5 m, the final velocity v is -5.2 m/s.
v = at + v₀
-5.2 m/s = (-9.8 m/s²) t + 5.2 m/s
t = 1.06 s
The unconscious mind plays a large role in Sigmund Freud's psychoanalysis<span>. He discussed the importance of the unconscious mind in understanding conscious thought and behaviour. </span><span>Sigmund Freud
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