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3 years ago

When describing the interaction between magnetic poles we could say that

Physics

2 answers:

kifflom [539]3 years ago

8 0

The Answer Is A
Hope This Helps !

Klio2033 [76]3 years ago

8 0

The answer here in my opinion is <span>A.north and south poles attract each other.
</span>

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2 % of freshwater is locked in ______.

oksano4ka [1.4K]

According to the internet over 2% of earths fresh water is unavailable: locked up in glaciers, polar ice caps, atmosphere, and soil.

5 0

3 years ago

Some kids are playing by rolling a skateboard across level ground beside a 0.75 m high wall. The goal is to drop from the wall v

lys-0071 [83]

Answer:

The speed of the kid and the skateboard together is 0.723 m/s

Explanation:

Let the mass of the kid be $m_{k} = 45 kg$

Let the mass of the skateboard be $m_{s} = 4,5 kg$

The initial speed of the skateboard, $v_{s} = 8 m/s$

The initial horizontal speed of the boy as he jumps on the skateboard, $v_{k} = 0 m/s$

Let the speed of the kid and the skateboard together be v

According to the principle of conservation of momentum:

$m_{k} v_{k} + m_{s} v_{s} = (m_{k} + m_{s}) v$

Substituting the appropriate values into the given equation

$(45*0) + (4.5*8) = (45 + 4.8) v$

36 = 49.8 v

v = 36/49.8

v = 0.723 m/s

7 0

4 years ago

Can you put this image back together? Type the correct order of letters below.

Art [367]

Answer:

CABD

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6 0

2 years ago

A nonconducting solid sphere of radius 8.40 cm has a uniform volume charge density. The magnitude of the electric field at 16.8

mina [271]

Answer:

The sphere's volume charge density is 2.58 μC/m³.

Explanation:

Given that,

Radius of sphere R= 8.40 cm

Electric field $E= 2.04\times10^{3}\ N/C$

Distance r= 16.8 cm

We need to calculate the sphere's volume charge density

Using Gauss's law

$\int{\vec{E}\cdot\vec{da}}=\dfrac{Q_{enc}}{\epsilon_{0}}$

$E\times 4\pi r^2=\dfrac{1}{\epsilon_{0}}\times\dfrac{4}{3}\piR^3\rho$

$E=\dfrac{\rho R^3}{3\epsilon_{0}r^2}$

$\rho=\dfrac{3\times E\times\epsilon_{0}r^2}{R^3}$

Put the value into the formula

$\rho=\dfrac{3\times2.04\times10^{3}\times8.85\times10^{-12}\times(16.8\times10^{-2})^2}{(8.40\times10^{-2})^3}$

$\rho=2.58\times10^{-6}\ C/m^3$

$\rho=2.58\ \mu C/m^3$

Hence, The sphere's volume charge density is 2.58 μC/m³.

5 0

4 years ago

A car initially traveling at 15 m/s North accelerates to 25 m/s North in 4 seconds. The magnitude of the average acceleration is

GarryVolchara [31]

The average acceleration of the car as it accelerates from 15 m/s to 25 m/s will be 2.5 m/s².

<h3>What is Average acceleration?</h3>

Average acceleration is the average rate of change of velocity with respect to time. Mathematically -

a = Δv/Δt

Given that a car is traveling at 15 m/s in north direction and in 4 seconds it accelerates to 25 m/s in the north direction only. Therefore, we can write -

initial velocity [u] = 15 m/s

final velocity [v] = 25 m/s

time taken [Δt] = 4 s

The magnitude of the average acceleration can be calculated as follows-

a = Δv/Δt

Δv = v - u = 25 - 15

Δv = 10 m/s

Therefore -

a = 10/4

a = 2.5 m/s².

Therefore, the average acceleration of the car will be 2.5 m/s².

To solve more questions on Acceleration, visit the link below-

brainly.com/question/21300541

#SPJ1

4 0

1 year ago